Question

Factorise: 8+(b^2-2)^4-6(b^2-2)^2

Answer 1

Answer:

Step-by-step explanation:

Let u = (b^2-2)^2

Now you have 8+u^2-6u = u^2-6u+8

= (u-4)(u-2)

= ((b^2-2)^2-4)((b^2-2)^2-2)

= (b^2-4b)(b^2-4b+2)

= b(b-4)(b-2-$\sqrt{6}$)(b-2+$\sqrt{6}$)