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7nadin3 [17]
3 years ago
6

Factorise: 8+(b^2-2)^4-6(b^2-2)^2

Mathematics
1 answer:
Ronch [10]3 years ago
8 0

Answer:

Step-by-step explanation:

Let u = (b^2-2)^2

Now you have 8+u^2-6u = u^2-6u+8

= (u-4)(u-2)

= ((b^2-2)^2-4)((b^2-2)^2-2)

= (b^2-4b)(b^2-4b+2)

= b(b-4)(b-2-\sqrt{6})(b-2+\sqrt{6})

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