Rule: The diagonals of any parallelogram bisect each other. In other words, they cut each other in half.
This means DF is cut into two equal pieces: DH and HF.
Similarly, GE is cut into two equal pieces: GH and HE.
DH = HF
x+5 = 2y
x = 2y-5
GH = HE
4x-3 = 4y+1
4(x)-3 = 4y+1
4(2y-5)-3 = 4y+1 ... x has been replaced with 2y-5
8y-20-3 = 4y+1
8y-23 = 4y+1
8y-4y = 1+23
4y = 24
y = 6
If y = 6, then x is
x = 2y-5
x = 2(6)-5
x = 12-5
x = 7
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Answers:
x = 7 and y = 6
Sum of two numbers is 62?
Let's call the two numbers
![a](https://tex.z-dn.net/?f=a)
and
![b](https://tex.z-dn.net/?f=b)
let's find two same numbers that would add up to 62: 31.
31 + 31 = 62
since it said the difference is 8, we have to add 4 to one number and subtract 4 from another.
31 - 4 = 27
31 + 4 = 35
Therefore, the two numbers following the given rules are 27 and 35
Answer:
32n
Step-by-step explanation:
4(8n) = 4 * 8 * n = 32 * n = 32n
thank, 5 star, and brainliest if helpful!
Answer:
Step-by-step explanation:
480?