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3 years ago

In how many places did the japanese troops land on december 8, 1941?

1 answer:

7 0

The first battle in the Pacific between the empire of Japan against the US and its allies took place on December 8, 1941. The Japanese forces began their conquest on the pacific islands and it started its invasion of the Malaya. They were held by a resistance of British Indian fighter however it was not enough to hold off the overwhelming Japanese force.

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Can someone help me with this ASAP??

Lena [83]

Answer:

3/5

Step-by-step explanation:

because bc is 2/5 away from each other while bd is 5/5 away from each other. 5/5 - 2/5 = 3/5

8 0

3 years ago

Read 2 more answers

The choir at wise middle school was preparing for their Hispanic concert. While rehearsing their opening song they noticed it to

Dominik [7]

Answer:

45.88 seconds

Step-by-step explanation:

$t_1$ = Time taken to sing the fist time = $48.7\ \text{s}$

Time taken to sing the second time was $2.9\ \text{s}$ less than the first time so

$t_2=t_1-2.9\\\Rightarrow t_2=48.7-2.9\\\Rightarrow t_2=45.8\ \text{s}$

Time taken to sing the third time was $0.47\ \text{s}$ less than the the second time

$t_3=t_2-0.47\\\Rightarrow t_3=45.8-0.47\\\Rightarrow t_3=45.88\ \text{s}$

So the time it took the choir to sing the third time was 45.88 seconds.

8 0

3 years ago

Building A is 255 meters taller than building B. If the height of building A is subtracted from twice the height of building B,

garri49 [273]

Answer:

A = 744 meters B = 489 meters

Step-by-step explanation:

A = B + 255

2B - A = 234

-2B -2B Subract the -2B from both sides

-A = -2B + 234

A = 2B - 234 Divide by -1 to get A alone

B + 255 = 2B - 234 Set both equations equal to each other

- B -B

255 = B - 234

+234 +234

489 = B

Plug 234 in for B in the original equations

A = 489 + 255

A = 744

8 0

3 years ago

Girardo is using the model below to solve the equation 3x+1=4x+(-4)

svp [43]

Answer:

Step-by-step explanation:

$3x+1=4x+(-4)\qquad\text{subtract}\ 4x\ \text{from both sides}\\\\3x-4x+1=4x-4x-4\\\\-x+1=-4\qquad\text{subtract 1 from both sides}\\\\-x+1-1=-4-1\\\\-x=-5\qquad\text{change the signs}\\\\x=5$