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Ne4ueva [31]
3 years ago
11

In how many places did the japanese troops land on december 8, 1941?

Mathematics
1 answer:
bezimeni [28]3 years ago
7 0
The first battle in the Pacific between the empire of Japan against the US and its allies took place on December 8, 1941. The Japanese forces began their conquest on the pacific islands and it started its invasion of the Malaya. They were held by a resistance of British Indian fighter however it was not enough to hold off the overwhelming Japanese force.
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What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? The figures ar
Sergeeva-Olga [200]

Answer: 5/2 and 25/4

Step-by-step explanation:

6x5=30

6x2=12

...

say these were perfect squares,

12x12= 144

30x30= 900

900/144 = 25/5

8 0
3 years ago
5. Draw the number line graph of -3.
love history [14]
Idk if this is what you’re looking for but here you go

5 0
3 years ago
4.80952380952 in fraction form
vladimir2022 [97]

Answer:

77/16

Step-by-step explanation:

8 0
3 years ago
HELP! WILL GIVE BRAINLEST
trasher [3.6K]

Answer:

Option C: 41

Step-by-step explanation:

<ABD+<CBD=90

<ABD=8x+1

<CBD=6x+5

(8x+1)+(6x+5)=90

Combine like terms

(8x+6x)+(1+5)=90

14x+6=90

14x=90-6

14x=84

divide both sides by 14

x=6

Now we plug that value into <DBC = 6x+5

6(6)+5=

36+5

41

7 0
2 years ago
Read 2 more answers
Which expression represents the number
frozen [14]

Answer:

8 + i

Step-by-step explanation:

What you need to simplify this is the following "definitions" of i to different powers.

i^1=i

i^2=-1

i^3=i^2*i=-1*i=-i

i^4=1

Now we can sub these in for the various powers of i in our expression:

6(1)+6(-i)-2(-1)+\sqrt{-1*49}

Simplifying a bit:

6-6i+2+\sqrt{i^2*49}

Since we know that the square root of i-squared is i, and that the square root of 49 is 7, we can get rid of the radial sign as follows:

6 - 6i + 2 + 7i

And the final answer, in a + bi form, is

8 + i

7 0
3 years ago
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