Answer:
1 left
Step-by-step explanation:
3 - 2 =1 You subtract then u get your answer
Hope this help u
Pls mark brainlist
LCM stands for least common multiple. We are being asked to find the lowest multiple that 6 and 15 have in common.
Multiples of a number (n) are integers that are the product of n and another number. Let's list the multiples of both 6 and 15:
6: 6, 12, 18, 24, 30, 36
15: 15, 30, 45, 60, 75, 90
The LCM of 6 and 15 is 30.
The values of x at wich F(x) has local minimums are x = -2 and x = 4, and the local minimums are:
<h3>
What is a local maximum/minimum?</h3>
A local maximum is a point on the graph of the function, such that in a close vicinity it is the maximum value there. So, on an interval (a, b) a local maximum would be F(c) such that:
c ∈ (a, b)
F(c) ≥ F(x) for ∀ x ∈ [a, b]
A local minimum is kinda the same, but it must meet the condition:
c ∈ (a, b)
F(c) ≤ F(x) for ∀ x ∈ [a, b]
A) We can see two local minimums, we need to identify at which values of x do they happen.
The first local minimum happens at x = -2
The second local minimum happens at x = 4.
B) The local minimums are given by F(-2) and F(4), in this case, the local minimums are:
If you want to learn more about minimums/maximums, you can read:
brainly.com/question/2118500
I think (7,10)
I hope that I helped ;D
Answer:
B. (1,7)
Step-by-step explanation:
We can substitute the x and y values of each coordinate into the inequality and test if they work.
Let's start with A, 5 being y and 0 being x .
5 IS NOT greater than 5, they are the exact same, so A is out.
Let's try B, 1 being x and 7 being y.
7 IS greater than 6, so B. (1,7) does work for this inequality!
Let's do C for fun, when 7 is x and 1 is y.
1 IS NOT greater than 12, it is quite less than 12, so C doesn't work.
Therefore B. (1,7) works for the inequality of 
.
Hope this helped!
