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3 years ago

Which of the following best approximates the value g(h(1))?

Mathematics

1 answer:

34kurt3 years ago

6 0

Answer:

Option (B)

Step-by-step explanation:

From the graph attached,

There are two functions 'f' and 'g' graphed.

Value of the function 'h' at x = 1,

y = h(1) = 0

Now we know g[h(1)] = g(0) [By substituting the value of h(1) = 0]

Therefore, value of the function 'g' at x = 0,

y = g(0) = -5 [y-intercept at x = 0]

Option (B) will be the correct option.

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15. a)

frutty [35]

Answer:

The correct answer is - A)8% B) 3%

Step-by-step explanation:

A) Let assume:

the cost price of the goods - $y.

the selling price of the goods - $x.

Given: The retailer sold at 4% discount, or 0.96x (100% - 4% = 96%). Since the goods were sold to make 20% profit, therefore it was sold for:

1.2y (100% + 20% = 120%).

Solution:

The refrigerator was sold at 13% VAT at Rs. 10848:

then,

=> 1.2y + 13%(1.2y) = 10848

=> 1.2y + 0.156y = 10848

=> 1.356y = 10848

=> y = 8000

Thus, the cp is Rs 8000.

The selling price is:

=> 0.96x = 1.2y

=> 0.96x = 1.2(8000)

=> x = 10000

The sp is Rs. 10000

For a profit of 15%, that is 1.15(8000) = 9200, the discount is:

(1 - discount)10000 = 9200

1 - discount = 0.92

Discount = 1 - 0.92 = 0.08 or 8%

B) Let C & M as cost price & marked price of the scanner machine respectively.

(1 + 20/100)*C = 41400

or (6/5)*C = 41400

or C = (5/6)*41400

= 34500 (Rs)

(1 - 10/100)*(1 + 15/100)*M = 41400

or (9/10)*(23/20)*M = 41400

or M = (10/9)*(20/23)*41400

= 40000 (Rs)

Let R% as the reduction in the percent in discount

(1 - 10/100 + R/100)*(1 + 15/100)*M

= (1 + 20/100 + 4/100)*C

or (9/10 + R/100)*(23/20)*40000

= (31/25)*34500

or 9/10 + R/100

= (20/23)(31/25)*(345/400)

or R/100 = 0.93 - 0.9 = 0.03

or R = 3%

7 0

3 years ago

Points A, B, C, and D are collinear and positioned in that order. Find the length indicated 7) Find BC if BC = 2x + 4, AD = 28,

belka [17]

Answer:

7) BC = 10

8) BD = 20

Step-by-step explanation:

7) The segment addition theorem tells you ...

AB +BC +CD = AD

(3x+2) +(2x+4) +(3x-2) = 28

8x +4 = 28 . . . . collect terms

8x = 24 . . . . . . . subtract 4

x = 3 . . . . . . . . . divide by 8

BC = 2x+4 = 2(3) +4

BC = 10

8) AB +BD = AC +CD

(2x -14) +(-7 +3x) = (2x -3) +(9)

5x -21 = 2x +6

3x = 27

x = 9

BD = -7 +3x = -7 +3(9)

BD = 20

7 0

3 years ago

A recipe that makes 8 jumbo blueberry muffins calls for 1 1/2

artcher [175]

The dozen is 36...36/8= 4.5. So 1.5x4.5=6.75 which converts to 6 3/4 teaspoons

5 0

3 years ago

Read 2 more answers

Kira needs 28 strawberries for every 4 smoothies she makes.

Stella [2.4K]

Answer:

Step-by-step explanation:

28/4=7 (So it is 7 strawberries for every smoothie)

7*3=21

4 0

3 years ago

Read 2 more answers

The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in

oksano4ka [1.4K]

Answer:

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

$p_v =P(Z>2)=0.0228$

Step-by-step explanation:

1) Data given and notation

$\bar X=8300$ represent the sample mean

$\sigma=1200$ represent the population standard deviation

$n=64$ sample size

$\mu_o =800$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

2) State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :

Null hypothesis: $\mu \leq 8000$

Alternative hypothesis: $\mu > 8000$

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

3) Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2$

4) P-value

Since is a one-side upper test the p value would given by:

$p_v =P(Z>2)=0.0228$

5) Conclusion

If we compare the p value and the significance level assumed, for example $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.

4 0

3 years ago