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4 years ago

Which of the following best approximates the value g(h(1))?

Mathematics

1 answer:

34kurt4 years ago

6 0

Answer:

Option (B)

Step-by-step explanation:

From the graph attached,

There are two functions 'f' and 'g' graphed.

Value of the function 'h' at x = 1,

y = h(1) = 0

Now we know g[h(1)] = g(0) [By substituting the value of h(1) = 0]

Therefore, value of the function 'g' at x = 0,

y = g(0) = -5 [y-intercept at x = 0]

Option (B) will be the correct option.

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In a certain quiz that consists of 10 questions, each question after the first is worth 4 points more than the preceding questio

weqwewe [10]

Answer:

C. 26

Step-by-step explanation:

Let’s suppose that the first question is worth ‘’x’’ amount of points. Then the second question will be worth x+4, the third question x+8, the fourth question x+12, the fifth x+ 16, the sixth x+20, the seventh x+24, the eighth x+ 28, the ninth x+ 32, and the last one x + 36.

The sum of the points of all these questions is equal to 10x + 180. Since the quiz has a total of 360 points, then

10x + 180 = 360.

Solving for x we get:

X = 18.

This means that the first question is worth 18 points, the second one 22 points (18 +4), the third one 26 points(18+4+4), and so on.

8 0

3 years ago

What to numbers should go here

Nuetrik [128]

44 because 4 times 1 is 4 and 6 times 4 is 24 so in the answer would be 2240

5 0

4 years ago

If a coin is tossed three times, find probability of getting

Assoli18 [71]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

‣ A coin is tossed three times.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

‣ The probability of getting,

1) Exactly 3 tails

2) At most 2 heads

3) At least 2 tails

4) Exactly 2 heads

5) Exactly 3 heads

${\large{\textsf{\textbf{\underline{\underline{Using \: Formula :}}}}}}$

$\star \: \tt P(E)= {\underline{\boxed{\sf{\red{ \dfrac{ Favourable \: outcomes }{Total \: outcomes} }}}}}$

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

★ When three coins are tossed,

then the sample space = {HHH, HHT, THH, TTH, HTH, HTT, THT, TTT}

[here H denotes head and T denotes tail]

⇒Total number of outcomes $\tt [ \: n(s) \: ]$ = 8

1) Exactly 3 tails 

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: tails)} = \red{ \dfrac{1}{8}}$

2) At most 2 heads

[It means there can be two or one or no heads]

Here

• Favourable outcomes = {HHT, THH, HTH, TTH, HTT, THT, TTT} = 7

• Total outcomes = 8

$\therefore \sf Probability_{(at \: most \: 2 \: heads)} = \green{ \dfrac{7}{8}}$

3) At least 2 tails 

[It means there can be two or more tails]

Here

• Favourable outcomes = {TTH, TTT, HTT, THT} = 4

• Total outcomes = 8

$\longrightarrow \sf Probability_{(at \: least \: 2 \: tails)} = \dfrac{4}{8}$

$\therefore \sf Probability_{(at \: least \: 2 \: tails)} = \orange{\dfrac{1}{2}}$

4) Exactly 2 heads 

Here

• Favourable outcomes = {HTH, THH, HHT } = 3

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 2 \: heads)} = \pink{ \dfrac{3}{8}}$

5) Exactly 3 heads

Here

• Favourable outcomes = {HHH} = 1

• Total outcomes = 8

$\therefore \sf Probability_{(exactly \: 3 \: heads)} = \purple{ \dfrac{1}{8}}$

$\rule{280pt}{2pt}$

8 0

2 years ago

Thomas has $30 to spend at the amusement park. Rides cost $2 each and admission at the gate is $6. What is the maximum number of

Rudiy27

Answer:

B.2r+6=30

Explanation:

It costs $6 dollars just to get in. Subtract 6 from 30. 30-6=24

Divide 24 by 2. 24 divided by 2 equals 12.

7 0

3 years ago

Read 2 more answers

Cedric lives in an apartment and pays the following expenses each month: electric bill, ; TV streaming service, ; and rent, . Es

Lynna [10]

Answer:

ncjnudnf

Step-by-step explanation:

8 0

3 years ago