Assume that you only include whole numbers (1,2,3,4,5,6,7,8,9) and not 3.5 and such so if 1 is odd and less than 5 then it is 1 or 3, since 5 isn't included then the other number, to be less than 5 when added, must be 1+x<5 3+x<5 solve each 1+x<5 subtract 1 x<4 set of answers are 1,2,3
3+x<5 subtract 3 x<2 set of answer is 1 so the possible numbers are 1,2,3 that is 3 numbesr out of 9 so probability=(total desired outcomes)/(total possible outcomes) so disred outcomes=3 total possible=9 3/9=1/3 the probabiltiy is 1/3
