Answer:
2x^4-11x^3+68x-80
2x^4-4x^3-7x^3+14x^2-14x^2+28x+40x-80
2x^3(x-2)-7x^2(x-2)-14x(x-2)+40(x-2)
(x-2)(2x^3-7x^2-14x+40)
(x-2)(2x^3-4x^2-3x^2+6x-20x+40)
(x-2)(2x^2(x-2)-3x(x-2)-20(x-2))
(x-2)(x-2)(2x^3-3x-20)
(x-2)(x-2)(2x^2+5x-8x-20)
(x-2)(x-2)(x(2x+5)-4(2x+5))
(x-2)(x-2)(2x+5)(x-4)
(x-2)^2(2x+5)(x-4)
OK, I will try my best to help you out, young lad. Just kidding, I am young too!
OK, so first you have to assign variables.
Let's make the first number = x-5
the second number is =x
Now, set up an equation
4(x-5)+5(x)=74
Use the distributive property to simplify the equation.
4x-20+5x=74
simplify the problem to find x
9x-20=74
9x=94
x=10.4 or 94/9
Now, apply the answer..
We know that the second number, x = 10.4 ( or 94/9), so the larger number is...
94/9 - 5= 49/4 of 5.4
so the answers are
first number= 5.4 (fraction form- 49/4)
second number= 10.4 (94/9)
10•12= 120
so 120 is your answer
Answer:
x = 0, x = -4, and x = 6
Step-by-step explanation:
To find the zeros of this polynomial, we can begin by factoring out a common factor of each term. 'x' is a common factor. We can distribute this variable out, giving us:
f(x) = x(x²- 2x- 24)
Now, factor the polynomial inside of the parenthesis into its simplest form. Factors of -24 that add up to -2 are -4 and 6.
f(x) = x( x + 4) (x - 6)
From this, we can derive the zeros x = 0, x = -4 and x = 6.
- 6b > 42 or 4b > - 4
Divide by - 6. Divide by 4.
b < - 7 Or b > - 1
