Answer:
Step-by-step explanation:
A binary string with 2n+1 number of zeros, then you can get a binary string with 2n(+1)+1 = 2n+3 number of zeros either by adding 2 zeros or 2 1's at any of the available 2n+2 positions. Way of making each of these two choices are (2n+2)22. So, basically if b2n+12n+1 is the number of binary string with 2n+1 zeros then your
b2n+32n+3 = 2 (2n+2)22 b2n+12n+1
your second case is basically the fact that if you have string of length n ending with zero than you can the string of length n+1 ending with zero by:
1. Either placing a 1 in available n places (because you can't place it at the end)
2. or by placing a zero in available n+1 places.
0 ϵ P
x ϵ P → 1x ϵ P , x1 ϵ P
x' ϵ P,x'' ϵ P → xx'x''ϵ P
Let a,b & c be the number of cookies Adrian, Bobby and Calvin baked respectively.
(a+b+c)/3 =138
(a+b)/2 =136
a+b=272
a=272-b
(b+c)/2 =125
b+c=250
c=250-b
Sub a=272-b and c=250-b into (a+b+c)/3 =138,
(a+b+c)/3 =138
[(272-b)+b+(250-b)]/3 = 138
272-b+b+250-b = 414
-b = -108
b=108
From the above,
a=272-b
=272-108
a=164
c=250-b
=250-108
c=142
∵ a=164
b=108
c=142
∴ Adrian baked 164 cookies.
Bobby baked 108 cookies.
Calvin baked 142 cookies.
Answer:
(7,-11)
Step-by-step explanation:
x'=x-3
or x=x'+3=4+3=7
y'=y+6
y=y'-6
or y=-5-6=-11
so original point was (7,-11)
Answer:
Hi. so I don't have the answers but usually if you find the name of the website your homework is from (if should be at the bottom of the page) online you can also find the answers for it. Just letting you know for this homework and future references.
Step-by-step explanation:
If the teacher asks for you to show your work the website might not show you step by step but you can just say you did it on a separate page. hope this helps!
Answer The Greatest Common Factor of 16, 40, 68 is 4. But the GCF of 16s^3t, 40s^5 and 68t^2 is 1, as there are no common terms for these given alphanumeric terms.
Step-by-step explanation:
