Answer:
y = 1/4 x -3
Step-by-step explanation:
y = -4x + 3;
the slope of this equation is -4
we want the slope perpendicular to this
take the negative reciprocal
- (-1/4) = 1/4
so the slope of our line will be 1/4
we have the slope and a point so we can use point slope form
y-y1 = m (x-x1)
y--2 = 1/4(x-4)
y+2 = 1/4 (x-4)
we need to change it to slope intercept form (y=mx+b)
distribute
y+2 = 1/4 x -1/4*4
y+2 = 1/4x -1
subtract 2 from each side
y +2-2 = 1/4 x -1-2
y = 1/4 x -3
the slope is 1/4 and the y intercept is -3
Solving for the missing term and the missing coefficient (6a − )5a = ( ) a^2 − 35a
Let the missing term be X
Let the missing coefficient be Y
Therefore, (6a – X)5a = Y(a^2) – 35a
6a x 5a – X.5a = Y.a^2 – 35a
30a^2 – X.5a = Y.a^2 – 35a
Equating co-efficients,
30a^2 = Y.a^2; X.5a = 35a
30 = Y; 5X = 35
Y = 30; X = 7
Therefore, (6a-7)5a = 30 a^2 – 35a
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Y - 0.32y = (1 - 0.32)y = 0.68y
A trapezoid falls under the definition.
Hope it helped!
~JustastudentXD
Answer:
x=2<br/>y=1
Step-by-step explanation:
\left\{ \begin{array} { l } { 4 x + y = 9 } \\ { 3 x - 2 y = 4 } \end{array} \right.
4x+y=9,3x-2y=4
4x+y=9
4x=-y+9
x=\frac{1}{4}\left(-y+9\right)
x=-\frac{1}{4}y+\frac{9}{4}
3\left(-\frac{1}{4}y+\frac{9}{4}\right)-2y=4
-\frac{3}{4}y+\frac{27}{4}-2y=4
-\frac{11}{4}y+\frac{27}{4}=4
-\frac{11}{4}y=-\frac{11}{4}
y=1
x=\frac{-1+9}{4}
x=2
x=2,y=1