The percent of time the photographer spent negotiating with the bison greater than the time he spent taking pictures is 500%
<h3>Percentage</h3>
- Time spent taking pictures = 5 minutes
- Time spent negotiating = 30 minutes
Percentage of time negotiating greater than taking pictures = (difference in time) / time to take pictures × 100
= (30 - 5) / 5 × 100
= 25/5 × 100
= 5 × 100
= 500%
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Since
, we know that
follows a Poisson distribution with parameter
.
Now assuming
denote the mean and standard deviation of
, respectively, then we know right away that
and
.
So,
Let us take 'a' in the place of 'y' so the equation becomes
(y+x) (ax+b)
Step-by-step explanation:
<u>Step 1:</u>
(a + x) (ax + b)
<u>Step 2: Proof</u>
Checking polynomial identity.
(ax+b )(x+a) = FOIL
(ax+b)(x+a)
ax^2+a^2x is the First Term in the FOIL
ax^2 + a^2x + bx + ab
(ax+b)(x+a)+bx+ab is the Second Term in the FOIL
Add both expressions together from First and Second Term
= ax^2 + a^2x + bx + ab
<u>Step 3: Proof
</u>
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
Identity is Found
.
Trying with numbers now
(ax+b)(x+a) = ax^2 + a^2x + bx + ab
((2*5)+8)(5+2) =(2*5^2)+(2^2*5)+(8*5)+(2*8)
((10)+8)(7) =(2*25)+(4*5)+(40)+(16)
(18)(7) =(50)+(20)+(56)
126 =126
Mixture problem.
Ratio of 20% : 50% acids
=50-39 : 39-20
=11:19
total volume
=400L
vol. of 20% acid=400*(11/(11+19)=400*(11/30)=146.667 L
vol. of 50% acid=400*(19/(11+19)=253.333 L
Alternatively, use c=volume of 20%, d=vol of 50%
then
0.2c+0.5d=400*0.39
Since c+d=400, we have
0.2c+0.5(400-c)=400*0.39=156
solve for c:
0.3c=44
c=146.667 and d=400-c=253.333 as before.
Class I
Trailer hitches are divided into different classes on the basis of the weight that they will be supporting. The classes are Class I - V, after which the classes are Xtra Duty and finally the Commercial Duty class, which has the ability to support 20,000 lbs.
