All categories

3 years ago

What is blank divide by 84.8 = 10.6

Mathematics

2 answers:

shusha [124]3 years ago

6 0

x÷84.8=10.6

x/84.8=10.6

x=10.6x84.8

x=898.88

Double check:

898.88/84.8=10.6

This would be the correct answer for blank (x) /84.8

UNO [17]3 years ago

5 0

simply just multiply 84.8*10.6

84.8*10.6=898.88

Answer= 898.88

Check:

898.88/84.8= 10.6

You might be interested in

A jet plane can carry up to 200,000 liters of fuel. It used 130,000 liters of fuel during a flight. What percentage of the fuel

-Dominant- [34]

Given:

Capacity of jet plane = 200,000 liters of fuel

Fuel used during flight = 130,000 liters

To find:

The percentage of the fuel capacity it uses on this flight.

Solution:

According to the question, we need to find 130,000 is what percent of 200,000.

$\text{Required percentage}=\dfrac{\text{Fuel used during flight}}{\text{Capacity of jet plane}}\times 100$

$\text{Required percentage}=\dfrac{130000}{200000}\times 100$

$\text{Required percentage}=65$

Therefore, the jet plane uses 65 percent of fuel capacity during flight.

6 0

3 years ago

Find the surface area of the composite solid below. (2 ft, 2 ft, 2 ft, 3 ft)

elixir [45]

Answer:

44 sq. ft

Step-by-step explanation:

5(2^2) = 20

4(3x2) = 24

20+24 = 44

3 0

3 years ago

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighb

Sedbober [7]

Option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

<h3>What are the variance and standard deviation? </h3>

In statistics, variance is a measure of the variation of data from the mean, whereas standard deviation is the measure of the normal distribution of statistical data.

A contractor records the areas, in square feet, of a small sample of houses in a neighborhood to determine data about the neighborhood.

2,400; 1,750; 1,900; 2,500; 2,250; 2,100

we need to find which of the following represents the numerator in the calculation of variance and standard deviation.

(225 $)^{2}$ + (–425 $)^{2}$ + (–275 $)^{2}$ + (325 $)^{2}$ + (75 $)^{2}$ + (–75 $)^{2}$ = 423,750

(650 $)^{2}$ + (–150 $)^{2}$ + (–600 $)^{2}$ + (250 $)^{2}$ + (150 $)^{2}$ + (–300 $)^{2}$ = 980,000

(250 $)^{2}$ + (–400 $)^{2}$ + (–250 $)^{2}$ + (350 $)^{2}$ + (100 $)^{2}$ + (–50 $)^{2}$ = 420,000

92416.60

The variance is 84000

The standard deviation is 290

mean = (2400+1750+1900+2500+2250+2100)/6

mean = 2150

Subtract the data values from the mean to get

2400-2150 = 250

1750-2150 = -400

1900-2150 = -250

2500-2150 = 350

2250-2150 = 100

2100-2150 = -50

The differences are 250, -400, -250, 350, 100, -50

Then you square those values and add up the squares

(250)^2 + (-400)^2 + (-250)^2 + (350)^2 + (100)^2 + (-50)^2 = 420,000

Hence, option c is the correct answer which represents the numerator in the calculation of variance and standard deviation.

Learn more about variance;

brainly.com/question/14116780

8 0

2 years ago

Tammy is playing a game where she is trying to roll a three with a standard

patriot [66]

Answer:

3/4 is the probablity

Step-by-step explanation:

7 0

4 years ago

Each year, all final year students take a mathematics exam. It is hypothesised that the population mean score for this test is 1

Yuri [45]

Answer:

90% confidence interval for the population mean test score is [95.40 , 106.59]

Step-by-step explanation:

We are given that the population mean score for mathematics test is 115. It is known that the population standard deviation of test scores is 17.

Also, a random sample of 25 students take the exam. The mean score for this group is 101.

The, pivotal quantity for 90% confidence interval for the population mean test score is given by;

P.Q. = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, X bar = sample mean = 101

$\sigma$ = population standard deviation

n = sample size = 25

So, 90% confidence interval for the population mean test score, $\mu$ is ;

P(-1.6449 < N(0,1) < 1.6449) = 0.90

P(-1.6449 < $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.6449) = 0.90

P(-1.6449 * $\frac{\sigma}{\sqrt{n} }$ < ${Xbar-\mu}$ < 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

P(X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ < $\mu$ < X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ) = 0.90

90% confidence interval for $\mu$ = [ X bar - 1.6449 * $\frac{\sigma}{\sqrt{n} }$ , X bar + 1.6449 * $\frac{\sigma}{\sqrt{n} }$ ]

= [ 101 - 1.6449 * $\frac{17}{\sqrt{25} }$ , 10 + 1.6449 * $\frac{17}{\sqrt{25} }$ ]

= [95.40 , 106.59]

Therefore, 90% confidence interval for the population mean test score is [95.40 , 106.59] .

7 0

4 years ago