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Factorize the quadratic trinomial by the rule:
1. Find the roots:
2. Factorize the polynomial:
3. Only factor x-2 is given in options, then the correct choice is B.
Answer:
The three angles of the triangle given above are 23, 73 and 84 correct to the nearest degree. The concept of dot product under vectors was applied in solving this problem. The three positions forming the triangle were taken as positions vectors. The Dot product also known as scalar product is a very good way of finding the angle between two vectors. ( in this case the sides of the triangle given above). Below is a picture of the step by step procedure of the solution.
Step-by-step explanation:
The first thing to do is to treat the given positions in space as position vectors which gives us room to perform vector manipulations on them. Next we calculate the magnitude of the position vector which is the square root of the sun of the square of the positions of the vectors along the three respective axes). Then we calculate the dot product. After this is calculated the angle can then be found easily using formula for the dot product.
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Based on the information provided, = at a bearing angle of = 59.88° .
We are requested to calculate the overall displacement of the ship, both in magnitude and direction, once it departs the harbor under the stated parameters. First, let's define a bearing.
<h3>What is bearing in the context given above?</h3>Angles are generally measured anticlockwise from the positive x-axis, whereas bearing angles are evaluated clockwise from the positive y-axis. A bearing is NOT a standard angle measuring tool.
Therefore, a bearing of 44.0° indicates that this is an angle 90.0° - 44.0° = 46°. This is the angle to be used in the calculations.
We're given that the first displacement is 11.4° at an angle of 46° (which was computed earlier).
Step 1 - Split the above into components
x1 = 11.4 Cos 46°
= 7.92m
y1 = 11.4Sin 46.0°
= 11.4 * 0.71933980033
= 8.2m
The second displacement is a simple 6.2mi due east, that is, the positive
x-direction. The components are thus:
Δx = x1 + x2
= 7.92 + 6.2
= 14.12mi
Δy = 1 + y2
= 8.2 + 0
= 8.2
r = √(x total)² + (y total)²
=√[(14.21)²+(8.2)²]
= √(201.9241 +67.24)
= √269.1641
= 16.4mi
The direction of the displacement vector is given by:
tan Ф = (Δy)/(Δx)
= arctan (8.2/14.12)
= arctan (0.5807365439)
= 30.12°
Recall that we were asked for the bearing angle. The bearing angle is what we get when we subtract 30.12° from 90°.
That is:
= 90 - 30.12
= 59.88°
Learn more about bearing angle:
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