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belka [17]
3 years ago
6

James has a piece of construction paper with an area of 50 1/4 inches. It is 4 3/16 inches long. What is the width of the piece

of construction paper in inches?
Mathematics
1 answer:
Flura [38]3 years ago
6 0

Answer:

The width of the piece of construction paper is 12 inches.

Step-by-step explanation:

The length of the construction paper=   4 3/16 in log

4\frac{3}{16} = 4 +  \frac{3}{16} = 4 + 0.1875 = 4.1875

⇒Length of the paper = 4.1875 inches

Let the width of the paper = w inches

The area of the paper = 50 1/4   sq. inches.

50\frac{1}{4} = 50 +  \frac{1}{4} = 50 + 0.25 = 50.25

⇒Area of the  paper = 50.25 sq. inches

Now, Area of the paper = LENGTH x WIDTH

or, 50.25 sq. inches  = 4.1875 inches x w

⇒ w = 50.25  / 4.1875 = 12 in

or, w = 12 in

Hence, the width of the piece of construction paper is 12 inches.

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You have a handful of dimes and quarters that totals 26 coins and is worth $5.15. How many of each do you have?
borishaifa [10]

Answer:

9 dimes and 17 quarters

Step-by-step explanation:

9+17=26 coins

9 dimes = 90 cents

17 = 425 cents

90+425= 515 cents or $5.15

Hope this helps! :)

5 0
2 years ago
What is 692,004 number in the other forms standard form?
Studentka2010 [4]
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6 0
3 years ago
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Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?
jeka94

by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression  x2 + 20 = 2x or , x^2 + 20 = 2x .

We know that Quadratic formula is :

x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

x^2 + 20 = 2x

⇒ x^2-2x+20=0

a=1\\b=-2\\c=20

Putting this value in equation x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a} :

⇒ x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}

⇒ x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}

⇒ x = \frac{2 \pm \sqrt{4-80}}{2}

⇒ x = (\frac{2 \pm 2i\sqrt{19}}{2})

⇒ x = 1 \pm (1)i\sqrt{19}}

Therefore , by Quadratic formula , x^2 + 20 = 2x , values of x are x = 1 \pm (1)i\sqrt{19}} . None of mentioned options are correct according to question!

7 0
3 years ago
20 = -d + 6
Sphinxa [80]

ok so rearrange things so that it says 6-d=20, then subtract six from each side to get -d=20-6, then subtract 6 from 20 to get -d=-14, then multiply both sides by -1 to get rid of the negative sign in front of the d since a variable cannot be a negative thus making your answer -14 or letter D. :) ❤❤❤❤

hope this helps

3 0
3 years ago
Read 2 more answers
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