Okay, so a general rule for finding perpendicular lines in the form of y = mx + b is y = (-1/m) + b.
First, let's ignore b (-7) because we're going to find that later.
A perpendicular line to y = 4x + b is y = -1/4x + b.
Alright, so now let's plug in the values. They are in the form of (x,y), so let's plug them in accordingly.
3 = -1/4(4) + b
3 = -1 + b
b = 4
y = -1/4x + 4
So a line perpendicular to y = 4x - 7 is y = -1/4x + 4.
Answer:

Step-by-step explanation:
17/20
Multiply by the conjugate 5/5.
(17 × 5)/(20 × 5)
85/100
Apply rule : a/100 = a%
85/100 = 85%
Answer: AB = 12.5, BC = 15
<u>Step-by-step explanation:</u>
Perimeter of ΔBCD = BC + CD + BD. Since it is an isoceles triangle, then BC = CD = BD. So, Perimeter of ΔBCD = 3BC
3BC = 45
<u>÷3 </u> <u>÷3 </u>
BC = 15
Perimeter of ΔABC = AB + BC + AC. Since it is an isosceles triangle with BC as the base, then AB = AC. So, Perimeter of ΔABC = 2AB + BC
2AB + BC = 40
2AB + 15 = 40
<u> -15</u> <u> -15 </u>
2AB = 25
<u>÷2 </u> <u>÷2 </u>
AB = 12.5
Answer:

Step-by-step explanation:
We have a circle that is split in three sections, two of which we know and we are asked to find the third missing section.
For the circle, we know that 4/5 and 1/10 is fit. Now we need the last one, to solve, we need to get the same denominator and see how much is missing.
Since 1/10 is our highest denominator, let's change 4/5 to have 10 as a denominator. Which would be through multiplying 5 to get 10.
What times 5 equals 10?
2
Now multiply both numerator and denominator by 2 to get our portion.


Now we have the same denominator, let's add our two fractions and see how much we have left.
8/10 + 1/10
9/10
We have 1/10 missing, therefore 1/10 is the answer.
Answer: q³⁰
Explanation:
First just solve the first part using the exponent rules
p²q⁵ becomes 1/p-⁸q-²⁰ then we flip the fraction so the exponents become positive. Now we have p⁸q²⁰.
Before multiplying the other equation, we must simplify. p-⁴q⁵ becomes 1/p⁴q-⁵ and since it's the exponents being raised to a power we simply multiply the inner exponents times the outer exponent which yields 1/p⁸q-¹⁰. We must make q-¹⁰ positive so we will then bring it to the numerator of the fraction which gives us: q¹⁰/p⁸.
Multiply q¹⁰/p⁸ * p⁸q²⁰/1 = p⁸q³⁰/p⁸ divide the p exponents by each other which yields 0 since when u divide exponents you just subtract them so 8 - 8 = 0. Your answer is now q³⁰/1 or just q³⁰