we know that
The probability that "at least one" is the probability of exactly one, exactly 2, exactly 3, 4 and 5 contain salmonella.
The easiest way to solve this is to recognise that "at least one" is ALL 100% of the possibilities EXCEPT that none have salmonella.
If the probability that any one egg has 1/6 chance of salmonella
then
the probability that any one egg will not have salmonella = 5/6.
Therefore
for all 5 to not have salmonella
= (5/6)^5 = 3125 / 7776
= 0.401877 = 0.40 to 2 decimal places
REMEMBER this is the probability that NONE have salmonella
Therefore
the probability that at least one does = 1 - 0.40
= 0.60
the answer is
0.60 or 60%
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452
4
One in 1200 are not particularly good odds. On the other hand, winning the lotto is 1 chance in 13,000,000 which if you've ever played the lotto you know that those odds are good enough to insure that if you played for the rest of your life and you are 18 not expect to live to 80 and you have 104 [given 2 draw a week] chances of winning per year, it likely won't happen. One in 1200 is better but still not good, especially with only 1 draw.
3
As a fraction her probability of winning is 1/2000 which is 0.000833333 as a decimal. You can put that in as
1
÷
1200
=
if you are not sure how your calculator works.
2
Sample Space = {1,2,3,4 .... 1198,1199,1200}
The outcome depends on sophies number. Either 1 number can be chosen or all of them can.
1
The sample space is the integers from 1 to 1200 inclusive.
Hello :
(-6a)-(-3a) =(-3a)-(0) = (0)-(3a) = (3a)-(6a) = -3a (arthmetic<span> sequence, the common - diff is : d= -3a the first term is : U1 = 6a
</span><span>a general rule for the n th term is : Un =U1+(n-1)d
Un = 6a +(n-1)(-3a) =
Un = 6a -3an+3a
</span>Un = -3an +9a