Let w represents the weight of the box .
It is given that , the weight, w, of the box may vary by no more than 3 pounds.
That is
Adding 25
And that's the required range .
Answer:
Step-by-step explanation:
Step 1: Apply the rule
![\left(-64\right)=-64\\\\=\sqrt[3]{-64}](https://tex.z-dn.net/?f=%5Cleft%28-64%5Cright%29%3D-64%5C%5C%5C%5C%3D%5Csqrt%5B3%5D%7B-64%7D)
Step 2: Apply the radical rule
![\sqrt[3]{-64}=-\sqrt[3]{64}\\\\=-\sqrt[3]{64}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B-64%7D%3D-%5Csqrt%5B3%5D%7B64%7D%5C%5C%5C%5C%3D-%5Csqrt%5B3%5D%7B64%7D)
Step 3: Factor the number
![\:64=4^3\\\\=-\sqrt[3]{4^3}](https://tex.z-dn.net/?f=%5C%3A64%3D4%5E3%5C%5C%5C%5C%3D-%5Csqrt%5B3%5D%7B4%5E3%7D)
Step 4: Apply the radical rule
![\sqrt[3]{4^3}=4\\\\=-4](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B4%5E3%7D%3D4%5C%5C%5C%5C%3D-4)
Therefore, ![\:\sqrt[3]{\left(\:-\:64\right)}\:=\:-4](https://tex.z-dn.net/?f=%5C%3A%5Csqrt%5B3%5D%7B%5Cleft%28%5C%3A-%5C%3A64%5Cright%29%7D%5C%3A%3D%5C%3A-4)
Answer: 6g^2+9g-6
Step-by-step explanation:(g+2)(6g−3)
=(g+2)(6g+−3)
=(g)(6g)+(g)(−3)+(2)(6g)+(2)(−3)
=6g^2−3g+12g−6
=6g^2+9g−6
That might not be as hard to answer as you just take the . away and then you're left with 249 centimeters :)
Answer:
Step-by-step explanation:
(-1,-2) , (3,10)
slope(m) = (10 - (-2) / (3 - (-1) = (10 + 2) / (3 + 1) = 12/4 = 3
y = mx + b
slope(m) = 3
u can use either of ur points....
(3,10)....x = 3 and y = 10
sub into the formula and find b, the y int
10 = 3(3) + b
10 = 9 + b
10 - 9 = b
1 = b
so ur equation is : y = 3x + 1
