Solve the equation: −4(+6)=−8
2 answers:
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Answer:
The probability is 0.02667
Step-by-step explanation:
Let's call D1 the event that the first radio is defective and D2 the event that the second radio is defective.
So, if we select both radios any factory, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = P(D2∩D1)/P(D1)
Taking into account that 0.02 is the probability that a radio produced at factory A is defective, P(D2/D1) for factory A is:
At the same way, if both radios are from factory B, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
Finally, if both radios are from factory C, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
So, if the radios are equally likely to have been any factory, the probability to select both radios from any of the factories A, B or C are respectively:
P(A)=1/3
P(B)=1/3
P(C)=1/3
Then, the probability P(D2/D1) that the second radio is defective given that the first one is defective is:
P(D2/D1) = (1/3)*(0.02) + (1/3)*(0.01) + (1/3)*(0.05)
P(D2/D1) = 0.02667
do you want me to make you a box and whisker plot if so then here
Answer:
a = 21
b = 63
c = 42√3
d = 21√3
Step-by-step explanation:
The sides of a 30°-60°-90° triangle have the ratios 1 : √3 : 2. The given side (42) is the longest side of the smallest triangle, and the shortest side of the largest triangle.
That means the other sides of the smallest triangle will be ...
a = 42/2 = 21
a+b = 2(42) = 84
b = (a+b) -a = 84 -21 = 63
d = 21√3 . . . . middle-length side of the smallest triangle
c = 42√3 . . . . middle-length side of the largest triangle
The values of the variables are ...
- a = 21
- b = 63
- c = 42√3
- d = 21√3
