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S_A_V [24]
3 years ago
7

What is the measure of ∠x?

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
The angle is a complementary angle so both angles add up to 90 degrees

Therefore set your equation equal to 90 to find angle of x

53+x=90

Subtract 53 from both sides

X= 37 degrees
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Which choice is the equation of the line that passes through the point (5, 19) and has a slope of
Liono4ka [1.6K]

Answer:

The equation is;

y = 12x-41

Step-by-step explanation:

Mathematically;

slope intercept form is;

y = mx + b

where m is slope and b is intercept

Since we already have the slope , the equation is;

y = 12x + b

To get b which is the y intercept, we simply substitute the value of the points given

Thus;

19 = 5(12) + b

19 = 60+ b

b = 19-60

b = -41

So the equation is;

y = 12x - 41

3 0
2 years ago
Math problem+Zoey, a Gelada Baboon, is tied to one of the outside corners of a regular hexagon-shaped research facility, where h
dexar [7]

Answer

The monkey will be able to cover an area of 22.86 meters which is equivalent to two sides and half of the building.

Step-by-step explanation:

The length of the monkeys rope = 75 feet long

Each side of the hexagon shaped facility = 30 feet

Note that, 1 feet = 0.3048 m

if we convert 30 feet to Meter, we have,

30 × 0.3048 = 9.144

Therefore, 30 + 30 +15 = 75 which is equivalent to the two side and half side of the hexagon shaped building

75 feet × 0.304 meter = 22.86 meters.

So the total area the monkey will be able to cover will be

= 22.86 Meters which is equivalent to two sides and half of the hexagon shape building.

8 0
3 years ago
A sample of 200 observations from the first population indicated that x1 is 170. A sample of 150 observations from the second po
igor_vitrenko [27]

Answer:

a) For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b) Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c)z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d) Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

Step-by-step explanation:

Data given and notation    

X_{1}=170 represent the number of people with the characteristic 1

X_{2}=110 represent the number of people with the characteristic 2  

n_{1}=200 sample 1 selected  

n_{2}=150 sample 2 selected  

p_{1}=\frac{170}{200}=0.85 represent the proportion estimated for the sample 1  

p_{2}=\frac{110}{150}=0.733 represent the proportion estimated for the sample 2  

\hat p represent the pooled estimate of p

z would represent the statistic (variable of interest)    

p_v represent the value for the test (variable of interest)  

\alpha=0.05 significance level given  

Concepts and formulas to use    

We need to conduct a hypothesis in order to check if is there is a difference between the two proportions, the system of hypothesis would be:    

Null hypothesis:p_{1} = p_{2}    

Alternative hypothesis:p_{1} \neq p_{2}    

We need to apply a z test to compare proportions, and the statistic is given by:    

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

a.State the decision rule.

For this case the value of the significanceis \alpha=0.05 and \alpha/2 =0.025, we need a value on the normal standard distribution thataccumulates 0.025 of the area on each tail and we got:

z_{\alpha/2} =1.96

If the calculated statistic |z_{calc}| >1.96 we can reject the null hypothesis at 5% of significance

b. Compute the pooled proportion.

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{170+110}{200+150}=0.8  

c. Compute the value of the test statistic.                                                                                              

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.    

Replacing in formula (1) the values obtained we got this:    

z=\frac{0.85-0.733}{\sqrt{0.8(1-0.8)(\frac{1}{200}+\frac{1}{150})}}=2.708    

d. What is your decision regarding the null hypothesis?

Since the calculated value satisfy this condition 2.708>1.96 we have enough evidence at 5% of significance that we have a significant difference between the two proportions analyzed.

5 0
3 years ago
14x25x4 breakdown using subraction distributive properties
WINSTONCH [101]
5x5x2x7x2x2 is the one i got


3 0
3 years ago
Read 2 more answers
Some electronic devices are better used than new: the failure rate is higher when they are new than when they are six months old
Reptile [31]
Given that half of the personal music players sold by a particular brand have a flaw. If the player has the​ flaw, it dies in the first six months. If it does not have this​ flaw, then only 20​% fail in the first six months.
Let A be the event that it fails in I 6 months
B1 = it has a flaw
B2 = it does not have a flaw
B1 and B2 are mutually exclusive and exhaustive
the chances that it has this​ flaw
=The probability that it has the flaw is

7 0
3 years ago
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