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IgorLugansk [536]
3 years ago
8

The Han dynasty lasted from 206 B.C. to 9 A.D. How many years did the dynasty last?

Mathematics
1 answer:
cricket20 [7]3 years ago
4 0

Answer:

The Han dynasty last was, 215 years

Step-by-step explanation:

Given statement: The Han dynasty lasted from 206 B.C. to 9 A.D.

To find how many years did the dynasty last.

B.C. represents Before Christ

A.D. represents After Death

To find the difference between two dates,

  • When the endings are the same you subtract
  • When they are different you add

You can see that the endings in the given 206 B.C. and 9 A.D. are B.C. and A.D. are different.

Just add these 206 and 9 we get;

206 + 9 = 215 years

Therefore, 215 years did the Han dynasty last.


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Solve each problem by writing and solving an equation
Viktor [21]

Answer:

The anwser would be 51 i think

Step-by-step explanation:

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3 years ago
What is the sum of 1 2/5 and 5 3/4​
Art [367]

Answer:

7\frac{3}{20}

Step-by-step explanation:

<em>Hey there!</em>

Well to add this we need to pu it in improper form.

7/5 + 23/4

Now we need to find the LCM.

5 - 5, 10, 15, 20, 25, 30

4 - 4, 8, 12, 16, 20, 24, 28

So the LCD is 20.

Now we need to change the 5 and 4 to 20.

5*4 = 20

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7 3/20

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4 0
3 years ago
Read 2 more answers
The Thompson Family decides to plant a total of 180 plants in order to prepare for a larger
Licemer1 [7]

Answer: 54 berry plants

Step-by-step explanation:

From the sample there are:

Lettuce = 12

Tomatoes = 6

Peppers = 3

Berries = 9

The total is: = 12 + 6 + 3 + 9 = 30 plants

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= 9/30

= 3/10 of the plants

If they want to plant a total of 180, the number of berrie plants needed is:

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8 0
3 years ago
BRAINLIEST ANSWER AND 98 POINTS!!!!
Alex73 [517]

Answer:

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25

P ( b1, g1 or g1 b2) = 3/20 + 3/20  = 6/20 = 3/10

P ( b1, g1 or g1 b2) = 1/10 + 1/10  = 2/10 = 1/5

Step-by-step explanation:

How many marbles are there?

5 green, 3 black, and 2 red marbles = 10 marbles

P ( green marbles) = green/ total = 5/10 = 1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (g1, g2) = P(g1) * P(g2) = 1/2 * 1/2 = 1/4


P ( red marble) = red/ total = 2/10 = 1/5

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (r1, r2) = P(r1) * P(r2) = 1/5 * 1/5 = 1/25


P ( black marble) = black/ total = 3/10

Then she puts it back, so there are still 10 marbles

P (2nd marble is green) = green/ total = 5/10 = 1/2

These are independent events ( since the marble is replaced)

P (b1, g2) = P(b1) * P(g2) = 3/10 * 1/2 = 3/20

This is if order matters, but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a black and green marble

The we multiply it by 2  because

P (b2, g1) = P(b2) * P(g1) = 1/2 * 3/10 = 3/20

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 3/20 + 3/20  = 6/20 = 3/10


P ( green marble) = green/ total = 5/10=1/2

Then she puts it back, so there are still 10 marbles

P (2nd marble is red) = red/ total = 2/10 = 1/5

These are independent events ( since the marble is replaced)

P (g1, r2) = P(g1) * P(r2) = 1/2 * 1/5 = 1/10

This is if order matters but I will assume order does not matter since the key word then is not there it just says and

If order doesn't matter, just that she has a green and red marble

The we multiply it by 2  because

P (r1, g2) = P(r1) * P(g2) = 1/5 * 1/2 = 1/10

We add the probabilities when it is or

P ( b1, g1 or g1 b2) = 1/10 + 1/10  = 2/10 = 1/5

3 0
3 years ago
Does anybody know the answer to this? (Also could I give the link to someone so they could help with the rest?)
Vesnalui [34]

Answer:

2x+168=166

2x= -2

x=-2

LMT= 94

Step-by-step explanation:

8 0
3 years ago
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