Hello!
To find the volume of the water, we would need to use the density formula. The density formula is d = m/V.
In this formula, d is the density, m is the mass and V is the volume.
1. To find the volume of 100 grams of ice, we substitute the appropriate values into the formula and solve for the volume using basic algebra.
0.92g/cm³ = 100g/V (multiply both sides by V)
0.92g/cm³ · V = 100g (divide both sides by 0.92g/cm³)
V = 108.69 cm³.
The volume of 100 grams of ice is about 108.69 cm³.
2. To find the volume of the completely melted ice, we would use the same formula, but the density is now 1.00 g/mL.
1.00g/mL = 100g/V (multiply both sides by V)
1.00g/mL · V = 100g (divide both sides by 1.00g/mL)
V = 100 mL
Therefore, the volume of the melted ice is 100 mL.
<u>Final answers</u>:
- 108.69 g/cm³
- 100 mL
Since this is an arithmetic sequence, you can conclude that
the addition to the number is constant.
Let x = the number asked
k = constant
number added to the sequence
7 + k = x
x + k = 17
Solve the system of equation:
7 + k + k = 17
7 + 2k = 17
2k = 10
k = 5
Therefore, the missing number is 12 (7 + 5).
Answer:
(1, 5)
Step-by-step explanation:
The solution to the system of equations is the point of intersection of the two lines. From inspection of the graph, the point of intersection is at (1, 5).
<u>Proof</u>
The solution to a system of equations is the point at which the two lines meet.
⇒ g(x) = f(x)
⇒ 3x + 2 = |x - 4| + 2
⇒ 3x = |x - 4|
⇒ 3x = x - 4 and 3x = -(x - 4)
⇒ 3x = x - 4
⇒ 2x = -4
⇒ x = -2
Inputting x = -2 into the 2 equations:
⇒ g(-2) = 3 · -2 + 2 = -4
⇒ f(-2) = |-2 - 4| + 2 = 8
Therefore, as the y-values are different, x = -2 is NOT a solution
⇒ 3x = -(x - 4)
⇒ 3x = 4 - x
⇒ 4x = 4
⇒ x = 1
Inputting x = 1 into the 2 equations:
⇒ g(1) = 3 · 1 + 2 = 5
⇒ f(1) = |1 - 4| + 2 = 5
Therefore, as the y-values are the same, x = 1 IS a solution
and the solution is (1, 5)
Answer:
A college student took 4 courses last semester. His final grades, along with the credits each class is worth, are as follow: A (3), B (4), C (2), and D (3). The grading system assigns quality points as follows: A: 4; B: 3; C: 2; D: 1; and F: 0. Find the student’s GPA for this semester. Round your answer to the nearest thousandth.
another way is
This is a weighted average question. You are going to "weight" each course by the number of credits it is worth and then divide by the total number of credits. In other words, you are going to multiply each grade (A=4, B=3) by the number of credits attached to that grade. This will ensure that the courses that have more credits count more in the overall average. Then you are going to divide by the total number of credits to get the overall GPA.
So,
(3*4 + 4*3 + 2 *2 + 3*1)/(3+4+2+3) = GPA
Step-by-step explanation:
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