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Ksju [112]
3 years ago
7

Ingrid received $110.00 for her birthday and plans to

Mathematics
1 answer:
AnnyKZ [126]3 years ago
7 0
18x6 = 108
110-108 =2
By weeks 6 she will only have $2 left
So being realistic, at week 7 she will have spent all her money.
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In AOPQ, o = 700 cm, p = 840 cm and q=620 cm. Find the measure of _P to the<br> nearest degree
Westkost [7]

Given:

In triangle OPQ, o = 700 cm, p = 840 cm and q=620 cm.

To find:

The measure of angle P.

Solution:

According to the Law of Cosines:

\cos A=\dfrac{b^2+c^2-a^2}{2bc}

Using Law of Cosines in triangle OPQ, we get

\cos P=\dfrac{o^2+q^2-p^2}{2oq}

\cos P=\dfrac{(700)^2+(620)^2-(840)^2}{2(700)(620)}

\cos P=\dfrac{490000+384400-705600}{868000}

\cos P=\dfrac{168800}{868000}

On further simplification, we get

\cos P=0.19447

P=\cos^{-1}(0.19447)

P=78.786236

P\approx 79

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A triangle has side lengths of (x-6), (x+2) and (x-9). Find the perimeter of the triangle
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Answer:

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Step-by-step explanation:

The perimeter is just the distance around the triangle. We have all three sides, so we can just add them together to get the total distance.

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Step-by-step explanation:

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