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3 years ago

If it's 11:50 A.M. right now, what time will it be, in 25 minutes?

Mathematics

2 answers:

Helga [31]3 years ago

7 0

The answer is 12:15 A.M.

Volgvan3 years ago

4 0

11:50am + 25 minutes = 12:15

Hope this helps

-AaronWiseIsBae

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Please help me. I suck at math

serg [7]

Answer:

Answer is ...Obtuse

Step-by-step explanation:

$\frac{m$

$\frac{5x + 4}{2} = \frac{3}{2} x + 21$

$\frac{5x + 4}{2} = \frac{3x + 42}{2}$

$5x + 4 = 3x + 42$

$5x - 3x = 42 - 4$

$2x = 38$

$x = 19$

$substituting \: x = 19 \: \:in \: \: \: \: \: \: \: \\ m$

We get,

m<ABC =

$(5 \times 19) + 4 = 99$

Hence <ABC is obtuse

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3 years ago

Quadrilateral KLMN is similar to quadrilateral OPQR. Find the measure of side QR.

Shalnov [3]

Answer: 12.6=13

Step-by-step explanation:

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2 years ago

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3 years ago

Find LCM of: x2 - 9, 3x3 + 81

VikaD [51]

Answer:

$\boxed{\pink{\sf (x + 3) \ is\ the \ LCM . }}$

Step-by-step explanation:

Given two expressions ,

$\qquad (1)\: x^2 - 9 \\\\ \qquad (2)\:3x^3 + 81$

And , we need to find the LCM , that is lowest common factor . So , let's factorise them seperately .

Factorising x² - 9 :- 

$= x^2 - 9 \\\\= x^2 - 3^2 \\\\ \red{= (x+3)(x-3)} \qquad\bf [Using \ a^2-b^2 = (a+b)(a-b) ]$

Factorising 3x³ + 81 

$= 3x^3 + 81\\\\= 3(x^3+27) \\\\= 3( x^3+27) \\\\ = 3(x^3+3^3) \\\\ \red{= 3 [ (x+3)(x^2+9-3x) ] } \qquad \bf{[ Using \ a^3+b^3=(a+b)(a^2+b^2-ab) ] }$

Hence we can see that (x+3) is common factor in both expressions.

Hence the LCM is ( x+3 ) .

8 0

2 years ago