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Vladimir [108]
3 years ago
13

Factor - 1/6 out of - 1/3x + 5/6y

Mathematics
1 answer:
Gemiola [76]3 years ago
7 0

\bf -\cfrac{1}{3}x\div -\cfrac{1}{6}\implies -\cfrac{1}{~~\begin{matrix} 3 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}x\div -\cfrac{\stackrel{2}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}}{1}\implies 2 \\\\\\ \cfrac{5}{6}y\div -\cfrac{1}{6}\implies \cfrac{5}{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}y\div -\cfrac{~~\begin{matrix} 6 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{1}\implies -5y \\\\[-0.35em] ~\dotfill

\bf -\cfrac{1}{3}x+\cfrac{5}{6}y\qquad \implies \qquad -\cfrac{1}{6}\left( 2x-5y \right)

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Simplify 4 to the 7th over 5 squared all raised to the 3rd power
alisha [4.7K]
<h2>Answer:</h2>

\left(\frac{4^{21}}{5^6}\right)

or

4 to the 21st over 5 to the 6th.

<h2>Step-by-step explanation:</h2>

First, we need to write our expression. Let's do it step by step:

<u>4 to the 7th:</u>

4^7

<u>5 squared:</u>

5^2

<u>4 to the 7th over 5 squared:</u>

\frac{4^7}{5^2}

<u>4 to the 7th over 5 squared all raised to the 3rd power:</u>

<u>\left(\frac{4^7}{5^2}\right)^3</u>

Using the law of exponents:

\left(\frac{4^{7\times 3}}{5^{2\times 3}}\right) \\ \\ \left(\frac{4^{21}}{5^6}\right)

Finally, the answer is 4 to the 21st over 5 to the 6th.

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Step-by-step explanation:

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