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Charra [1.4K]
2 years ago
9

(x+4)+(x-3)+(2x+2)+(x^2+3x+1)

Mathematics
1 answer:
rewona [7]2 years ago
8 0

Answer:

X^2+7x+4

Step-by-step explanation:

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4 - (y - 3) = 3(y + 1) - 4(1 - y)
s344n2d4d5 [400]

Answer:

The value of y is 1

Step-by-step explanation:

4 - (y - 3) = 3(y + 1) - 4(1 - y)

4 - y + 3 = 3y + 3 - 4 + 4y

7 - y = 7y - 1

7 + 1 = 7y + y

8y = 8

y = 1

Thus, The value of y is 1

<u>-</u><u>TheUnknownScientist</u><u> 72</u>

4 0
2 years ago
PLEASE HELP! DUE TONIGHT
Luden [163]

Answer:

B

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Use strong mathematical induction to prove the existence part of the unique factorization of integers theorem (Theorem 4.4.5). I
valentina_108 [34]

Answer:

Lets say that P(n) is true if n is a prime or a product of prime numbers. We want to show that P(n) is true for all n > 1.

The base case is n=2. P(2) is true because 2 is prime.

Now lets use the inductive hypothesis. Lets take a number n > 2, and we will assume that P(k) is true for any integer k such that 1 < k < n. We want to show that P(n) is true. We may assume that n is not prime, otherwise, P(n) would be trivially true. Since n is not prime, there exist positive integers a,b greater than 1 such that a*b = n. Note that 1 < a < n and 1 < b < n, thus P(a) and P(b) are true. Therefore there exists primes p1, ...., pj and pj+1, ..., pl such that

p1*p2*...*pj = a

pj+1*pj+2*...*pl = b

As a result

n = a*b = (p1*......*pj)*(pj+1*....*pl) = p1*....*pj*....pl

Since we could write n as a product of primes, then P(n) is also true. For strong induction, we conclude than P(n) is true for all integers greater than 1.

5 0
3 years ago
Find and simplify the product of the following rational expression
alekssr [168]
I would say it’s b

You can cross cancel (x-3) out of both fractions
Then you have x+2/ x times 3/4
Multiply the numerators
3(x+2)
And the denominators
x • 4 = 4x
Leaving you with 3(x+2)/4x
You can simplify it further into 3x+ 6/ 4x which is option b, though it is technically simplified with the parentheses.
6 0
2 years ago
What is the value of x in the equation 3x-4y =65, when y = 4? i will gift brainliest
Elenna [48]

Answer:

3x-4y=65

3x=65+4y

x=(65+4y)/3, when y=4

x=(65+4*4)/3

x=(65+16)/3

x=81/3

x=27

5 0
3 years ago
Read 2 more answers
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