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LenKa [72]
3 years ago
10

HEY CAN ANYONE PLS ANSWER DIS MATH QUESTION!!!

Mathematics
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

(-2,3) i cant graph im sorry

Step-by-step explanation:

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What is the value of this expression? (37)^0 0 3^7 1 30^7
Likurg_2 [28]

Answer:

1

Anything to the 0th power is 1.

5 0
3 years ago
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An alloy consists of nickel, zinc, and copper in the ratio 2:7:9. How many pounds of nickel have to be used to create alloy that
Hunter-Best [27]

We are given ratio nickel to zinc to copper = 2:7:9.

From this ratio we can see that <em>ratio of nickel to zinc is 2:7</em>.

Let us assume number of pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc is x pounds.

So, we can setup a proportion as :

x : 4.9 =  2:7

Or

\frac{x}{4.9}=\frac{2}{7}

On cross multiplication, we get

7x= 4.9× 2

7x = 9.8

Dividing both sides by 7, we get

x = 1.4.

<h3>Therefore, 1.4 pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.</h3><h3 />
6 0
3 years ago
4. Can two lines be parallel and perpendicular? Explain.
lidiya [134]

Answer: No

Step-by-step explanation: First, we need to understand that parallel lines are coplanar lines that do not intersect. On the other hand, perpendicular lines are lines that intersect at a right angle.

However, lines can't be both parallel and perpendicular because they either intersect each other at a right angle or never intersect.

So no, two lines can't be both parallel and perpendicular.

7 0
3 years ago
Hey so im also looking for the first answer and the choices were “ is not “ and “ is “
dexar [7]

so the investigator found the skid marks were 75 feet long hmmm what speed will that be?

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ d=75 \end{cases}\implies s=\sqrt{30(0.7)(75)}\implies s\approx 39.69~\frac{m}{h}

nope, the analysis shows that Charlie was going faster than 35 m/h.

now, assuming Charlie was indeed going at 35 m/h, then his skid marks would have been

s=\sqrt{30fd}~~ \begin{cases} f=\stackrel{friction}{factor}\\ d=\stackrel{skid}{feet}\\[-0.5em] \hrulefill\\ f=\stackrel{dry~day}{0.7}\\ s=35 \end{cases}\implies 35=\sqrt{30(0.7)d} \\\\\\ 35^2=30(0.7)d\implies \cfrac{35^2}{30(0.7)}=d\implies 58~ft\approx d

4 0
3 years ago
If quadrangles have all equal angles, are they congruent?
xenn [34]

Answer:

yes because it says all angles are the same

3 0
3 years ago
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