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3 years ago

Jasmine left the house at 7.10am and get back at 6.35pm.how long is she out of the house

2 answers:

8 0

Okay well the way I do it is like this. When ever the next hour hits 10 minutes that is one hour then add the minutes left. So from 7:10a.m. to 6:10p.m. is 11 hours. Now the rest of the minutes. 6:35 -6:10=:25. So she has been away from the house for 11 hours and 25 minutes

iragen [17]3 years ago

8 0

<h2>Answer:</h2>

The time she was out of the house is:

11 hours and 25 minutes.

<h2>Step-by-step explanation:</h2>

It is given that:

Jasmine left the house at 7:10 am and get back at 6:35 pm.

This means that she left the house in the morning and was back in evening.

Now, in order to calculate time we go by a simple technique:

7:10 am-8:10 am=1 hour

8:10 am-9:10 am=2 hour

9:10 am-10:10 am= 3 hour

10:10 am-11:10 am= 4 hour

11:10 am-12:10 pm= 5 hour

12:10 pm-1:10 pm= 6 hour

1:10 pm-2:10 pm= 7 hour

2:10 pm-3:10 pm= 8 hour

3:10 pm-4:10 pm= 9 hour

4:10 pm-5:10 pm= 10 hour

5:10 pm-6:10 pm= 11 hour

Also from 6:10 pm to 6:35 pm there are: 25 minutes.

This means that the total time she was out of the house is: 11 hours and 25 minutes.

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3 years ago

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Answer:

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3 years ago

Pls answer before 8:00 pm

Semenov [28]

Answer:225 jeans.

Step-by-step explanation: What we need to do here is convert the number of jeans to a percentage. There were 25 jeans when 50 customers were surveyed and 25 is half of 50 or 50%. This means that if 450 pairs of pants are ordered half of them should be jeans. 450/2 = 225.

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1 year ago

A pyramid has a square base of length 8cm and a total surface area of 144cm². Find the volume of the pyramid. (Please use Pythag

Sveta_85 [38]

Answer:

$\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

Step-by-step explanation:

we are given surface area and the length of the square base

we want to figure out the Volume

to do so

we need to figure out slant length first

recall the formula of surface area

$\displaystyle A_{\text{surface}}=B+\dfrac{1}{2}\times P \times s$

where B stands for Base area

and P for Base Parimeter

$\sf\displaystyle \: 144=(8 \times 8)+\dfrac{1}{2}\times (8 \times 4) \times s$

now we need our algebraic skills to figure out s

simplify parentheses:

$\sf\displaystyle \: 64+\dfrac{1}{2}\times32\times s = 144$

reduce fraction:

$\sf\displaystyle \: 64+\dfrac{1}{ \cancel{ \: 2}}\times \cancel{32} \: ^{16} \times s = 144 \\ 64 + 16 \times s = 144$

simplify multiplication:

$\displaystyle \: 16s + 64 = 144$

cancel 64 from both sides;

$\displaystyle \: 16s = 80$

divide both sides by 16:

$\displaystyle \: \therefore \: s = 5$

now we'll use Pythagoras theorem to figure out height

according to the theorem

$\displaystyle \: {h}^{2} + (\frac{l}{2} {)}^{2} = {s}^{2}$

substitute the value of l and s:

$\displaystyle \: {h}^{2} + (\frac{8}{2} {)}^{2} = {5}^{2}$

simplify parentheses:

$\displaystyle \: {h}^{2} + (4 {)}^{2} = {5}^{2}$

simplify squares:

$\displaystyle \: {h}^{2} + 16 = 25$

cancel 16 from both sides:

$\displaystyle \: {h}^{2} = 9$

square root both sides:

$\displaystyle \: \therefore \: {h}^{} = 3$

recall the formula of a square pyramid

$\displaystyle V_{pyramid}=\dfrac{1}{3}\times A\times h$

where A stands for Base area (l²)

substitute the value of h and l:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times \{8 \times 8 \}\times 3$

simplify multiplication:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{3}\times 64\times 3$

reduce fraction:

$\sf\displaystyle V_{ \text{pyramid}}=\dfrac{1}{ \cancel{ 3 \: }}\times 64\times \cancel{ \: 3}$

hence,

$\sf\displaystyle V_{ \text{pyramid}}= 64 \: {cm}^{3}$

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2 years ago

What is the solution to x – 10 > – 12?<br><br> (–∞, –18)<br> (–18, ∞)<br> (–∞, 18)<br> (18, ∞)

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Answer:

(18, ∞)

Step-by-step explanation:

(18, ∞) is the only option that works. if we ignore the "greater than" sign, and just set the function equal to -12, we see that x-10=-12 would give us x=-2. If we plug in -3 for x, we get -13, which is less than -12. if we plug in -1 for x, we get -11, which is greater than -12. Therefore, with the function only having one critical point (zero), we know that every value greater than -2 is a solution. Technically, the full solution would be (-2, ∞). however, the only answer available meeting the criteria would be (18, ∞).

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3 years ago

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