H(x) = -x² - 4
i(x) = 2x + 3
h(i(5)) = -(2(5) + 3) - 4
h(i(5)) = -(10 + 3) - 4
h(i(5)) = -(13) - 4
h(i(5)) = -13 - 4
h(i(5)) = -17
2(w+2)-8w=-14 -- expand the brackets, multiply the term(s) outside the bracket by the term(s) inside the bracket.
2w+4-8w=-14 -- combine like terms
4-6w=-14 -- add 6w to both sides and add 14 to both sides
18=6w
3=w
<u>w=3</u>
14 sec because
In 2sec=600
In4 sec=1200
In6 sec =1800
In 8sec =2400
In10 sec=3000
In12sec=3600
In 14sec=4000
In 14seconds it covers 4000
111 straw bundles / 4 per stall = 27.75
However, you can’t technically have a .75 of a stall, so you round down to the nearest whole number, which is 27.
Answer:
Step-by-step explanation: