Answer:
This is proved by ASA congruent rule.
Step-by-step explanation:
Given KLMN is a parallelogram, and that the bisectors of ∠K and ∠L meet at A. we have to prove that A is equidistant from LM and KN i.e we have to prove that AP=AQ
we know that the diagonals of parallelogram bisect each other therefore the the bisectors of ∠K and ∠L must be the diagonals.
In ΔAPN and ΔAQL
∠PNA=∠ALQ (∵alternate angles)
AN=AL (∵diagonals of parallelogram bisect each other)
∠PAN=∠LAQ (∵vertically opposite angles)
∴ By ASA rule ΔAPN ≅ ΔAQL
Hence, by CPCT i.e Corresponding parts of congruent triangles PA=AQ
Hence, A is equidistant from LM and KN.
Answer:
B. 45
Step-by-step explanation:
do 12×12 which is 144 then Davide it by 2 because it's a triangle then do 9×3 which is 27 then subtract that from 72 and you get 45.
Actually Welcome to the concept of Parallel lines.
We must first understand that, Parallel Lines always have a same Slope, hence the 'm' value in y=mx+c equation will same, here it is '1/2' in the above equation,
so the points here are (-6,-17)
==>
(y-(-17)) = m(x-(-6))
==>
here m = 1/2 ,hence
y+17 = 1/2(x+6)
==> y+17 = 1/2(x) + 3
==> y = 1/2(x) + 3 - 17
==> y = 1/2(x) - 14
hence the Option 4.) is the correct answer!!
Answer:
-15.96
Step-by-step explanation:
A conjugate is a binomial with the sign inside changed. So the conjugate of (1/5 + 4i) is (1/5 - 4i)
Set the original and the conjugate next to each other and F.O.I.L. Multiply the first numbers of each binomial, the 1/5 and the 1/5 to get 1/25. This is the "F."
Multiply the outer members, the 1/5 and the 4i to get - 60i. This is the "O."
Multiply the inner numbers ( the + 4i and the 1/5) to get + 60i. This is the "I."
Multiply the positive 4i and the negative 4i to get 16i squared
The positive 60i and the negative 60i cancel each other out.
The i squared changes into - 1. This makes the 16 negative.
Add 1/25 to - 16 to get - 15.96
A) triangle c, has the largest area
b) a= 1/2 (3) (3) a= 4.5
the picture shows what i mean hope this helps :)
