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andrew11 [14]
3 years ago
7

Jacob's Boat Rentals charges a one-time fee plus a $5 hourly rate to rent a boat. The cost to rent a boat for 2 hours is $25 and

the cost for 3 hours is $30. Which is the one-time fee to rent a boat?
Mathematics
1 answer:
maks197457 [2]3 years ago
7 0
Hi there! The answer is $15

Let the one-time fee be represented by X.
The total cost of hiring a boat for 2 hours is X + $5 per hour × 2 hours = X + $10

The total cost can also be expressed as $25.
Now we can set up an equation.
X + 10 = 25

Subtract 10.
X = 15

Therefore, the one-time fee to rent a boat is $15.

We can check this by plugging in the data for the rent of 3 hours.
$15 + $5 per hour × 3 hours =
$15 + $15 = $30, which is the correct answer.

In short:
The answer is $15
~ Hope this helps you!
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\hbox{between} \ \frac{3}{4}=\frac{3 \times 2}{4 \times 2}=\frac{6}{8} \ \hbox{and} \ \frac{7}{8} \\ \\ \frac{6}{8} < \frac{x}{8} < \frac{7}{8} \Rightarrow 6
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Margo is creating a pencil caddy in the shape of a triangular prism. She is determining how much wood she needs to build the cad
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Answer:

a little late

205 1/5 is your answer

Step-by-step explanation:

break down the 3-D figure

Find area of triangle A=1/2bh

=1/2(8 inch)(6   9/10inch)

=1/2(8 inch)(69/10 inch)

=138/5 square inch

then multiply two because you have 2 triangles

=138/5 (2)  

= 276/5 square inch

= 55 1/5 sq.in

Find area of rectangle

A = lw

=6 1/4 in (8 in)

= 25/4 (8 in.)

= 50 sq. in.

then multiply by 3 because of the three rectangles

= 50 sq. inch (3)

= 150 sq. in.

Add all together

55 1/5 sq. inch + 150 sq. inch = 205 1/5 sq. inch

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3 years ago
Please help? What is the tangent ratio of angle B?
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Answer:

Step-by-step explanation:

The tangent equation = side opposite angle / side beside angle

which in this case is tan\alpha =AC/ BC

which is the third choice

Hope that helps!

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We know that a token costs $1.75. If you purchase 10 tokens, you get 2 free tokens. Write and solve an equation to find the appr
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Answer:

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3 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


8 0
3 years ago
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