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3 years ago

13

Does a vertical asymptote acts like a break in continuity

1 answer:

sergey [27]3 years ago

8 0

I think you wanted to know whether the statement in question is true or false. based on this assumption i am answering the question. It is absolutely true that <span>a vertical asymptote acts like a break in continuity. I hope that this answer has actually come to your great help.</span>

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Simplify the following expressions using the properties of exponents.<br> Please show your work.

Rus_ich [418]

Answer:

${a}^{0} = 1 \\ {a}^{1} \times {a}^{4} = {a}^{4 + 1} = {a}^{5} \\ {4}^{2} = 16\\ \\ = \frac{2}{4 \times {4}^{2} \times {a}^{5} } \\ = \frac{1}{32 {a}^{5} }$

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2 years ago

Simplify -2(3x+6) -4(x-5)

Mkey [24]

-10x8

you distribute-2 through the parentheses & 4 too. Then you collect the like terms and calculate the sum.

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3 years ago

What is the area of triangle ABC?

miskamm [114]

Answer:

<h2>7 square units</h2>

Step-by-step explanation:

As you can observe in the image attached, we know the coordinates of each vertex of the triangle.

To find the area using only its vertex coordinates, we need to use the following formula

$A=\frac{1}{2}[x_{1}(y_{2} -y_{3}+x_{2}(y_{3} -y_{1} )+x_{3}(y_{1}-y_{2} ) )$

Where the coordinates are

$A(1,1)\\B(4,0)\\C(3,5)$

Replacing coordinates, we have

$A=\frac{1}{2}[1(0 -5)+4(5 -1 )+3(1-0 ) ]\\A=\frac{1}{2} [-5+16+3]=\frac{1}{2}(14)\\ A=7$

Therefore, the area of the triangle is 7 square units. So, the right answer is the second choice.

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3 years ago

12) Which polynomial function has a leading coefficient of 2, root-5 with multiplicity 3, and root 12 with multiplicity 1?

gogolik [260]

Answer:

A

Step-by-step explanation:

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3 years ago

What is the mean .median ,mode of 2,3,4,3,2

Eddi Din [679]

Answer:

Step-by-step explanation:

mean = total / amount of numbers

= 15/5 = 3

median = 4 middle number

mode = most common numbers = 3,2

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3 years ago