Answer:
Use the degree and the leading coefficient to determine the behavior.
Rises to the left and falls to the right
Step-by-step explanation:
8/3 is an improper fraction, to make it proper you find out how many times 3 goes into 8 (which is 2). So then you have 2 and two times 3 is 6. This does not equal 8 yet so you do 8-6=2 You put this number over the denominator 3. So your final answer is 2 2/3.
The circumference of the circle is 40π. Hope it help!
Answer: Letter B)
A=πr2
d=2r
A=1
4πd2=1
4·π·162≈201.06193
Step-by-step explanation:
Hope this Helps! : )
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<em><u>question</u></em><em><u> </u></em><em><u>⇩</u></em>
<em><u>✎</u></em><em><u> </u></em><em><u>The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.</u></em>
<em><u>The area of a newspaper page (opened up) is about 640.98 square inches. Determine the length and width of the page if its length is about 1.25 times its width.The width of the page is ___ inches.</u></em>
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<em><u>answer</u></em><em><u> </u></em><em><u>➡</u></em><em><u> </u></em><em><u> </u></em><em><u>1</u></em><em><u>.</u></em><em><u>2</u></em><em><u>4</u></em><em><u> </u></em><em><u>inches</u></em><em><u> </u></em></h3>
<em><u>hope</u></em><em><u> </u></em><em><u>it</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em>
<em><u>correct</u></em><em><u> </u></em><em><u>me</u></em><em><u> </u></em><em><u>if</u></em><em><u> </u></em><em><u>I</u></em><em><u> </u></em><em><u>am</u></em><em><u> </u></em><em><u>wrong</u></em><em><u> </u></em>
<h3>
<em><u> </u></em><em><u> </u></em><em><u> </u></em><em><u>by</u></em><em><u> </u></em><em><u> </u></em><em><u> </u></em></h3><h2>
<em><u>#</u></em><em><u>g</u></em><em><u>a</u></em><em><u>l</u></em><em><u>a</u></em><em><u>d</u></em><em><u>o</u></em><em><u>h</u></em><em><u>a</u></em><em><u>n</u></em><em><u>n</u></em><em><u>a</u></em><em><u>d</u></em><em><u>i</u></em><em><u>v</u></em><em><u>i</u></em><em><u>n</u></em><em><u>e</u></em><em><u>2</u></em><em><u>9</u></em></h2>