Answer:
Consider points (0, -5) and (-6, -1)
» General equation of a line:
![{ \tt{y = mx + c}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7By%20%3D%20mx%20%2B%20c%7D%7D)
- m is slope
- c is y-intercept
<u> </u><u>S</u><u>l</u><u>o</u><u>p</u><u>e</u><u> </u><u>(</u><u>m</u><u>)</u><u>:</u>
![{ \tt{m = \frac{ - 1 - ( - 5)}{ - 6 - 0} }} \\ \\ { \tt{m = \frac{4}{ - 6} }} \\ \\ { \tt{m = - \frac{2}{3} }}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7Bm%20%3D%20%20%5Cfrac%7B%20-%201%20-%20%28%20-%205%29%7D%7B%20-%206%20-%200%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Ctt%7Bm%20%3D%20%20%5Cfrac%7B4%7D%7B%20-%206%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Ctt%7Bm%20%3D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20%7D%7D)
<u> </u><u>y</u><u>-</u><u>i</u><u>n</u><u>t</u><u>e</u><u>r</u><u>c</u><u>e</u><u>p</u><u>t</u><u> </u><u>(</u><u>c</u><u>)</u><u>:</u>
![{ \tt{y = mx + c}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7By%20%3D%20mx%20%2B%20c%7D%7D)
consider point (0, -5)
![{ \tt{ - 5 = c}} \\ { \tt{c = - 5}}](https://tex.z-dn.net/?f=%7B%20%5Ctt%7B%20-%205%20%3D%20c%7D%7D%20%5C%5C%20%7B%20%5Ctt%7Bc%20%3D%20%20-%205%7D%7D)
Equation:
![{ \boxed{ \tt{y = - \frac{2}{3} x - 5}}}](https://tex.z-dn.net/?f=%7B%20%5Cboxed%7B%20%5Ctt%7By%20%3D%20%20-%20%20%5Cfrac%7B2%7D%7B3%7D%20x%20-%205%7D%7D%7D)
Answer:
i. 18 miles per hour is an outlier
ii. the outlier decreases the mean speed
Step-by-step explanation:
An outlier in a given data is one of the values that is far greater or lesser compared to others. It affect the mean and standard deviation of a given data significantly.
From the given data, 18 is far too small compared to other values. This is certainly an outlier. This would affect the mean speed by decreasing the value.
An interquartile range is a measure of differences among data by dividing a set of given data into quartile. Increasing the value of the outlier would increase the interquartile range.
k/jkjln/kjln/j
Please find the attached diagram for a better understanding of the question.
As we can see from the diagram,
RQ = 21 feet = height of the hill
PQ = 57 feet = Distance between you and the base of the hill
SR= h=height of the statue
=Angle subtended by the statue to where you are standing.
= which is unknown.
Let us begin solving now. The first step is to find the angle
which can be found by using the following trigonometric ratio in
:
![tan(x)=\frac{RQ}{PQ} =\frac{21}{57}](https://tex.z-dn.net/?f=%20tan%28x%29%3D%5Cfrac%7BRQ%7D%7BPQ%7D%20%3D%5Cfrac%7B21%7D%7B57%7D%20%20)
Which gives
to be:
![\angle x=tan^{-1}(\frac{21}{57})\approx20.22^{0}](https://tex.z-dn.net/?f=%20%5Cangle%20x%3Dtan%5E%7B-1%7D%28%5Cfrac%7B21%7D%7B57%7D%29%5Capprox20.22%5E%7B0%7D%20%20%20%20)
Now, we know that
and
can be added to give us the complete angle
in the right triangle
.
We can again use the tan trigonometric ratio in
to solve for the height of the statue, h.
This can be done as:
![tan(\angle SPQ)=\frac{SQ}{PQ}](https://tex.z-dn.net/?f=%20tan%28%5Cangle%20SPQ%29%3D%5Cfrac%7BSQ%7D%7BPQ%7D%20%20)
![tan(7.1^0+20.22^0)=\frac{SR+RQ}{PQ}](https://tex.z-dn.net/?f=%20tan%287.1%5E0%2B20.22%5E0%29%3D%5Cfrac%7BSR%2BRQ%7D%7BPQ%7D%20%20)
![tan(27.32^0)=\frac{h+21}{57}](https://tex.z-dn.net/?f=%20tan%2827.32%5E0%29%3D%5Cfrac%7Bh%2B21%7D%7B57%7D%20%20)
![\therefore h+21=57tan(27.32^0)](https://tex.z-dn.net/?f=%20%5Ctherefore%20h%2B21%3D57tan%2827.32%5E0%29%20)
![h\approx8.45 ft](https://tex.z-dn.net/?f=%20h%5Capprox8.45%20ft%20)
Thus, the height of the statue is approximately, 8.45 feet.
Ok so lets start with the 5 dozen there are 12 eggs in one dozen so we do 12*5 which gives us 60 and then we figure out what 3/4 of 12 is that sounds confusing the way i typed it. an example is make four piles each evenly numbered so four piles of three so take three of those piles which gives you the number nine so 60 + 9 gives you 69 so Jesse has 69 eggs.