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mihalych1998 [28]
3 years ago
10

The graph shows two lines, A and B.

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

second option: (4, 4) is the solution to both lines A and B.

Step-by-step explanation:

You know that the equation of line A is:

y=-3x+15

and the equation of line B is:

y=\frac{1}{2}x+2

The point in which the line A intersects with the line B is the solution of the sytstem of equations.

You can observe in given graph that the point of intersection of Line A and Line B is: (4,4)

Therefore (4, 4) is the solution to both lines A and B.

Svetach [21]3 years ago
6 0

Answer:

(4, 4) is the solution to both lines A and B.

Step-by-step explanation:

Given graph shows two lines, A and B.

Based on the graph, we need to find about which statement is correct about the solution to the system of equations for lines A and B. Where give choices are:

(4, 4) is the solution to line A but not to line B.

(4, 4) is the solution to both lines A and B.

(5, 1) is the solution to line B but not to line A.

(0, 2) is the solution to both lines A and B.

From graph we can see that both lines intersect at point (4,4). Since solution lies on both lines so the correct choice is:

(4, 4) is the solution to both lines A and B.

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a solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned
Jlenok [28]

Question:

A solar lease customer built up an excess of 6,500 kilowatts hour (kwh) during the summer using his solar panels. when he turned his electric heat on, the excess be used up at 50 kilowatts hours per day .

(a) If E represents the excess left and d represent the number of days. Write an equation for E in terms of d

(b) How much of excess will be left after one month (1 month = 30 days)

Answer:

a. E = 6500 - 50d

b. E = 5000

Step-by-step explanation:

Given

Excess = 6500kwh

Rate = 50kwh/day

Solving (a): E in terms of d

The Excess left (E) in d days is calculated using:

E = Excess - Rate * days

The expression uses minus because there's a reduction in the excess kwh on a daily basis.

Substitute values for Excess, Rate and days

E = 6500 - 50 * d

E = 6500 - 50d

Solving (b); The value of E when d = 30.

Substitute 30 for d in E = 6500 - 50d

E = 6500 - 50 * 30

E = 6500 - 1500

E = 5000

<em>Hence, there are 5000kwh left after 30 days</em>

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3 years ago
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Answer:

Step-by-step explanation:

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Step-by-step explanation:

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