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masya89 [10]
2 years ago
14

Working alone, Darryl can mop a warehouse in 11 hours. Elisa can mop the same warehouse in 9

Mathematics
1 answer:
Harrizon [31]2 years ago
3 0

Answer:

  • ≈ 5 hours

Step-by-step explanation:

<u>Time needed if they work together:</u>

  • 1 / (1/11 + 1/9) =
  • 1/ (20 / 99) =
  • 99/20 ≈ 5 hours
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If the probability of surviving a head on car accident at 55 mph is 0.097, then what is the probability of not surviving
BabaBlast [244]

The probability of not surviving a head-on car accident is: 0.903

Step-by-step explanation:

The probabilities of occurrence and non-occurrence of an event add up to one.

If p is the probability that an even will happen and q is the probability that it will not happen

Then

p+q=1

Here,

Probability of surviving = p = 0.097

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The probability of not surviving a head-on car accident is: 0.903

Keywords: Probability, Inverse

Learn more about probability at:

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  • brainly.com/question/4464845

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5 0
3 years ago
Given a leading coefficient of 8, polynomial roots of 1 &amp; 2, and the known point on the graph (4,5). Write an equation that
m_a_m_a [10]

Given:

The leading coefficient of a polynomial is 8.

Polynomial roots are 1 and 2.

The graph passes through the point (4,5).

To find:

The 3rd root and the equation of the polynomial.

Solution:

The factor form of a polynomial is:

y=a(x-c_1)(x-c_2)...(x-c_n)

Where, a is a constant and c_1,c_2,...,c_n are the roots of the polynomial.

Polynomial roots are 1 and 2. So, (x-1) and (x-2) are the factors of the polynomial.

Let the third root of the polynomial by c, then (x-c) is a factor of the polynomial.

The leading coefficient of a polynomial is 8. So, a=8 and the equation of the polynomial is:

y=8(x-1)(x-2)(x-c)

The graph passes through the point (4,5). Putting x=4,y=5, we get

5=8(4-1)(4-2)(4-c)

5=8(3)(2)(4-c)

5=48(4-c)

Divide both sides by 48.

\dfrac{5}{48}=4-c

c=4-\dfrac{5}{48}

c=\dfrac{192-5}{48}

c=\dfrac{187}{48}

Therefore, the 3rd root on the polynomial is \dfrac{187}{48}.

8 0
2 years ago
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