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masya89 [10]
2 years ago
14

Working alone, Darryl can mop a warehouse in 11 hours. Elisa can mop the same warehouse in 9

Mathematics
1 answer:
Harrizon [31]2 years ago
3 0

Answer:

  • ≈ 5 hours

Step-by-step explanation:

<u>Time needed if they work together:</u>

  • 1 / (1/11 + 1/9) =
  • 1/ (20 / 99) =
  • 99/20 ≈ 5 hours
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Mademuasel [1]

Answer:

I'm doing the same thing and, I don't understand it either.

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Answer:

790  for surface area

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Step-by-step explanation:

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3 years ago
Is finding a car's depreciation over a 10 year period considered as univariate or bivariate?
g100num [7]

Determining a car's depreciation over a ten year period is considered a bivariate.

<h3>What is a bivariate?</h3>

A Bivariate data is made up of two variables that are observed against each other. In determining the deprecation of a car, the cost of the car is observed against the passage of time and the depreciation factor.  

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8 0
2 years ago
Q.6. The equation of the ellipse whose centre is at the origin and the x-axis, the major axis, which passes
azamat

<h3>Answer:</h3>

Equation of the ellipse = 3x² + 5y² = 32

<h3>Step-by-step explanation:</h3>

<h2>Given:</h2>

  • The centre of the ellipse is at the origin and the X axis is the major axis

  • It passes through the points (-3, 1) and (2, -2)

<h2>To Find:</h2>

  • The equation of the ellipse

<h2>Solution:</h2>

The equation of an ellipse is given by,

\sf \dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1

Given that the ellipse passes through the point (-3, 1)

Hence,

\sf \dfrac{(-3)^2}{a^2} +\dfrac{1^2}{b^2} =1

Cross multiplying we get,

  • 9b² + a² = 1 ²× a²b²
  • a²b² = 9b² + a²

Multiply by 4 on both sides,

  • 4a²b² = 36b² + 4a²------(1)

Also by given the ellipse passes through the point (2, -2)

Substituting this,

\sf \dfrac{2^2}{a^2} +\dfrac{(-2)^2}{b^2} =1

Cross multiply,

  • 4b² + 4a² = 1 × a²b²
  • a²b² = 4b² + 4a²-------(2)

Subtracting equations 2 and 1,

  • 3a²b² = 32b²
  • 3a² = 32
  • a² = 32/3----(3)

Substituting in 2,

  • 32/3 × b² = 4b² + 4 × 32/3
  • 32/3 b² = 4b² + 128/3
  • 32/3 b² = (12b² + 128)/3
  • 32b² = 12b² + 128
  • 20b² = 128
  • b² = 128/20 = 32/5

Substituting the values in the equation for ellipse,

\sf \dfrac{x^2}{32/3} +\dfrac{y^2}{32/5} =1

\sf \dfrac{3x^2}{32} +\dfrac{5y^2}{32} =1

Multiplying whole equation by 32 we get,

3x² + 5y² = 32

<h3>Hence equation of the ellipse is 3x² + 5y² = 32</h3>
8 0
3 years ago
Find the reference angle of 100 degrees
Roman55 [17]

Since the angle  

100 °  is in the second quadrant, the reference angle formula is  A r = 180 ° −

A c.   A r = 180 ° − 100 °

The reference angle is  A r = 80 ° .

80 °

4 0
2 years ago
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