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Kitty [74]
3 years ago
12

How do you solve X/2-5=10

Mathematics
1 answer:
Afina-wow [57]3 years ago
5 0

Answer: x2-5=10  

Two solutions were found :

                  x = ± √15 = ± 3.8730

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x2"   was replaced by   "x^2".  

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    x^2-5-(10)=0  

Step by step solution :

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  x2-15  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 15 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Equation at the end of step  1  :

 x2 - 15  = 0  

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    x2-15 = 0  

Add  15  to both sides of the equation :  

                     x2 = 15

 

When two things are equal, their square roots are equal. Taking the square root of the two sides of the equation we get:  

                     x  =  ± √ 15  

The equation has two real solutions  

These solutions are  x = ± √15 = ± 3.8730  

 

Two solutions were found :

                  x = ± √15 = ± 3.8730

Step-by-step explanation:

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