Answer:
When they are equal, y=y, so we can say:
x^2+5x-2=x+1 subtract x from both sides
x^2+4x-2=1 add 2 to both sides
x^2+4x=3, now add half the linear coefficient squared, (4/2)^2=4
x^2+4x+4=3+4 now the left side is a perfect square
(x+2)^2=7 now take the square root of both sides
x+2=±√7 subtract 2 from both sides
x=-2±√7
x=-2+√7 and -2-√7
y=x+1 the two points where these equations are equal are:
(-2-√7, -1-√7) and (-2+√7, -1+√7)
or approximately:
(-4.65, -3.65) and (0.65, 1.65)
Answer:
x^2-12x+27
Step-by-step explanation:
(x-3)(x-9)=x^2-3x-9x+27=x^2-12x+27
Answer:
go to 7 on the y Axis, point it, the go up 1 and over 2, then point that.
Multiply both the top and bottom by 8 8/9=64/72
multiply both the top and bottom by 9 1/8=9/72
9 goes fully into in to 63 7 times
7 is your answer.
