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Goryan [66]
3 years ago
9

Solve for x. 4x − 3/ 3 =7 Enter your answer in the box. x =

Mathematics
2 answers:
Ivanshal [37]3 years ago
8 0

Answer:

6

Step-by-step explanation:

I'm going to assume you mean (4x - 3) / 3 = 7

If that is not correct, could you please correct it.

Multiply both sides by 3

3*(4x - 3) / 3 = 7*3

The 3s cancel on the left

4x - 3 = 21  

Add 3 to both sides.

4x - 3 + 3 = 21 + 3

combine

4x = 24

Divide by 4

4x/4 = 24/4

x = 6

Agata [3.3K]3 years ago
4 0

Answer:

x = 6

Step-by-step explanation:

(4x - 3)/3 = 7

4x - 3 = 21

4x = 24

x = 6

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A data set of 27 different numbers has a mean of 33 and a median of 33. A new data set is
Svetllana [295]

Answer:

Option D.

Step-by-step explanation:

Suppose that we have a set of N values:

{x₁, x₂, ..., xₙ}

The median is the value in the middle, and the mean is calculated as:

M = \frac{(x_1 + x_2 + x_3 ... + x_n)}{N}

Because here we have "the median" then we will assume that N is odd, and there is only one median, the value "k"  (if N was even, the median would be the mean of the two middle values, that case is really similar to the case where N is odd, so solving only one of the cases is enough)

Now we add 7 to all the values greater than the median

We subtract 7 to all values smaller than the median.

Then the median remains unchanged (because we did not add nor subtract anything to the median).

The new mean will be:

M' = \frac{(x_1 - 7) + (x_2 - 7) + ... + (x_{k}) + ... + (x_n + 7)}{N} = \frac{(x_1 + x_2 + ... + x_n) + (-7)*(n/2 - 0.5) + 7*(n/2 - 0.5)}{N}  = \frac{(x_1 + x_2 + ... + x_n)}{N} = M

So the mean does not change.

Because the mean is computed as the sum of the numbers divided by N, and the mean does not change, and N does not change, then the sum of the numbers does not change.

Finally, the standard deviation is computed as:

SD = \sqrt{\frac{(x_1 - M)^2 + ... + (xn - M)^2}{N} }

Because M does not change, if we add or subtract numbers to some of the values, the standard deviation will change (Because all the terms are squared, so the added and subtracted sevens don't cancel like in the previous cases)

Then the only value that does not have the same value in both the original and new data sets is the standard deviation.

6 0
3 years ago
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Akimi4 [234]

Answer:

is that math????????????????

3 0
3 years ago
The newsstand at the corner of Manilla Avenue and GreenTree Rd. in GreenTree sells the daily edition of The Pittsburgh Press. Th
Pavlova-9 [17]

Answer:

1 - NORM.DIST(625, 600, 15 ,TRUE)

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In Excel:

We use the norm.dist command.

NORM.DIST(x, mean, standard_dev ,cumulative)

x is the tested value, mean and standard_dev are the mean and the standard deviation, while cumulative we use true to find a probability of a value lower than x, so for a value higher than x, we use:

1 - NORM.DIST(x, mean, standard_dev ,TRUE)

Mean of 600 copies and a standard deviation of 15 copies.

mean = 600, standard_dev = 15

You want to find the probability of selling more than 625 newspapers on any given day.

x = 625

What is the Excel Command

1 - NORM.DIST(625, 600, 15 ,TRUE)

6 0
3 years ago
Plz answer these plz i failing math
victus00 [196]
Gauge 4 I am pretty sure
8 0
4 years ago
Read 2 more answers
The line of reflection will (always, sometimes, never) be the perpendicular bisector between a preimage and it’s reflected image
frez [133]

Answer:

Step-by-step explanation:

line of reflection: <em>a fixed line directly in the middle of the pre-image and the reflected image. </em>

perpendicular: <em>two lines meeting at a 90 degree angle</em>

bisector: <em>line that divides something into two equal parts</em>

pre-image: <em>the original figure before any transformation or translation has been made</em>

reflected image: <em>the original image after being reflected across the line of reflection.</em>

<em />

Is the line of reflection a line running perpendicular, directly in the middle of the pre-image and the reflected image? Yes, always would be my answer.

6 0
4 years ago
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