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neonofarm [45]
3 years ago
12

Find the total area for the regular pyramid. T.A. xxx(sqr) + xx (sqr)x

Mathematics
1 answer:
N76 [4]3 years ago
5 0
We are to solve the total area of the pyramid and this can be done through area addition. We first determine the area of the base using the Heron's formula.
                           A = √(s)(s - a)(s - b)(s - c)
where s is the semi-perimeter
                                 s = (a + b + c) / 2
 Substituting for the base,
                               s = (12 + 12 + 12)/ 2 = 18
                          A = (√(18)(18 - 12)(18 - 12)(18 - 12) = 62.35
Then, we note that the faces are just the same, so one of these will have an area of,
                                s = (10 + 10 + 12) / 2 = 16
                                  A = √(16)(16 - 12)(16 - 10)(16 - 10) = 48
Multiplying this by 3 (because there are 3 faces with these dimensions, we get 144. Finally, adding the area of the base,
                          total area = 144 + 62.35 = 206.35
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Step-by-step explanation:

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Can someone explain this please???
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ss7ja [257]

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A triangle is graphed in the coordinate plane. The vertices of the triangle have coordinates (–3, 1), (1, 1), and (1, –2). What
vladimir2022 [97]

Answer:

The perimeter of the triangle is 12\ units

Step-by-step explanation:

Let

A(-3,1),B(1,1),C(1,-2)

we know that

The perimeter of triangle is equal to

P=AB+BC+AC

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

step 1

Find the distance AB

A(-3,1),B(1,1)

substitute in the formula

AB=\sqrt{(1-1)^{2}+(1+3)^{2}}

AB=\sqrt{(0)^{2}+(4)^{2}}

AB=4\ units

step 2

Find the distance BC

B(1,1),C(1,-2)

substitute in the formula

BC=\sqrt{(-2-1)^{2}+(1-1)^{2}}

BC=\sqrt{(-3)^{2}+(0)^{2}}

BC=3\ units

step 3

Find the distance AC

A(-3,1),C(1,-2)

substitute in the formula

AC=\sqrt{(-2-1)^{2}+(1+3)^{2}}

AC=\sqrt{(-3)^{2}+(4)^{2}}

AC=5\ units

step 4

Find the perimeter

P=AB+BC+AC

substitute the values

P=4+3+5=12\ units

6 0
4 years ago
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