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sattari [20]
4 years ago
7

An adiabatic closed system is accelerated from 0 m/s to 30 m/s. Determine the specific energy change of this system, in kJ/kg.

Physics
1 answer:
snow_tiger [21]4 years ago
6 0

Answer:

Explanation:

initial velocity, u = 0 m/s

final velocity, v = 30 m/s

Let the mass is m .

Initial kinetic energy, Ki = 1/2 mu² = 0

Final kinetic energy, Kf = 1/2 mv² = 0.5 m x 30 x 30 = 450 m

Specific energy change = change in kinetic energy per unit mass

                                         = 450 m / m = 450 J/kg = 0.45 kJ/kg

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Put the value into the formula

U_{B}=-\dfrac{6.67\times10^{-11}\times940\times5.98\times10^{24}}{6.38\times10^{6}+11.10\times10^{6}}

U_{B}=-2.14\times10^{10}\ J

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Using formula of k_{A}

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Using formula of k_{B}

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We need to calculate the work done

Using formula of work done

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W=(k_{B}-k_{A})+(U_{B}-U_{A})

W=(-\dfrac{U_{B}}{2}+\dfrac{U_{A}}{2})+(U_{B}-U_{A})

W=\dfrac{1}{2}(U_{B}-U_{A})

Put the value into the formula

W=\dfrac{1}{2}\times(-2.14\times10^{10}+3.44\times10^{10})

W=6.5\times10^{9}\ J

Hence, The required work done is 6.5\times10^{9}\ J

7 0
3 years ago
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