I think the answer is 2 km south. This is because when someone moves 4km south and moves 2km north, the final position 2km south. and if the person moves 5 km farther north,the position is now 3km north and if he moves 5km south, the final position is 2km south.
False
we can calculate it at a specific time by taking the derivative of positive function, which gives us the functional form of instantaneous velocity v(t)
Do you see the places in the question where it says all the things like ...
-- that YOU assembled
-- the voltage and resistance of each bulb
-- the measured total voltage and total current
-- the values that YOU calculated
-- use YOUR data
-- change in equivalent resistance, voltage drop across each bulb, and total voltage
These ALL refer to information that you were given before you started the exercise, or to measurements that you were supposed to measure. So first of all, we don't have the information that was given to you before the exercise. Regarding the measurements, either you measured them, or else you didn't measure them. If you DID measure them, we need to know the measurements in order to answer the questions, because ALL of the questions are asking about those measurements. If you DIDN't measure them, then the information we need to answer the questions <em>doesn't exist anywhere</em>, until somebody goes and measures them. So, anybody who would like to just hand you a bunch of answers is totally stuck ... IF the answers even exist, we don't have ANY of the information needed to find them with.
Answer:
110000000 m/s²
Explanation:
From Newton's equation of motion,
v² = u²+2as ................... Equation 1
Where v = final velocity of the space capsule, u = initial velocity of the space capsule, a = acceleration of the space traveler, s = length of the cannon.
make a the subject of the equation,
a = (v²-u²)/2s................ Equation 2
Given: v = 220 km/s = 220000 m/s. u = 0 m/s (As the space capsule was initially at rest), s = 220 m.
Substitute into equation 2
a = (220000²-0)/(2×220)
a = 48400000000/440
a = 110000000 m/s²
Hence the unrealistic large acceleration = 110000000 m/s²
