Ask question

Ask question

All categories

just olya [345]

3 years ago

11

The friction between a nonmoving object and the surface is resting on is called..?

1 answer:

Tamiku [17]3 years ago

7 0

Answer:

Static friction exists between a stationary object and the surface on which it is resting. It prevents an object from moving against the surface. Example: Static friction prevents an object like a book from falling of the desk, even if the desk is slightly tilted

Explanation:

hope this helped

You might be interested in

A particle beam is made up of many protons, each with a kinetic energy of 3.25times 10-15 J. A proton has a mass of 1.673 times

ArbitrLikvidat [17]

Answer:

The magnitude of a uniform electric field that will stop these protons in a distance of 2 m is 1.01 x $10^{-4}$ N/C

Explanation:

given information,

kinetic energy, KE = 3.25 x $10^{-15}$ J

proton's mass, m = 1.673 x $10^{-27}$ kg

charge, q = 1.602 x $10^{-19}$ C

distance, d = 2 m

to find the electric field that will stop the proton, we can use the following equation:

E = F/q

= (KE/d) / q , KE = Fd --> F = KE/d

= KE/qd

= (3.25 x $10^{-15}$ J) / (1.602 x $10^{-19}$ C)(2 m)

= 1.01 x $10^{-4}$ N/C

3 0

3 years ago

The blade of a windshield wiper moves through an angle of 180.0 degrees in 0.500 s. The tip of the blade moves on the arc of a c

sweet-ann [11.9K]

Answer:

Centripetal acceleration will be equal to $10.66m/sec^2$

Explanation:

We have given time taken to cover 180° is 0.5 sec

So time taken by 360° is equal to = 2×0.5 = 1 sec

Radius of the circle r = 0.520 m

So distance $d=2\pi r=2\times3.14\times 0.520=3.2656m$

So velocity $v=\frac{distance}{time}=\frac{.2656}{1}=3.2656m/sec$

We have to find the centripetal acceleration

Centripetal acceleration will be equal to $a_c=\frac{v^2}{r}=\frac{3.2656^2}{1}=10.66m/sec^2$

So centripetal acceleration will be equal to $10.66m/sec^2$

7 0

4 years ago

You are holding one end of a horizontal stretched string. Flicking your wrist will send a pulse down the string. Which actions w

kumpel [21]

Answer:

Use a lighter string of the same length, under the same tension.

Stretch the string tighter to increase the tension

Explanation:

The wave speed depends on propertices of the medium, not on how you generate the wave. For a string

Increasing the tension or decreasing the linear density (lighter string) will increase the wave speed.

5 0

3 years ago

Has anyone done this???i need the last questions for 1 and 2

Helen [10]

Answer:

no i haven't done it

Explanation:

clean yo computer tho

8 0

3 years ago

This is for Criminal Law:

tigry1 [53]

No it not because
Jill didn’t have actually have the gun

8 0

3 years ago