P=I^2 *R
600 =5.0^2 *R
R=24
Answer: 24 ohms
I hope it’s correcttttttt...
Answer:
0.231 N
Explanation:
To get from rest to angular speed of 6.37 rad/s within 9.87s, the angular acceleration of the rod must be

If the rod is rotating about a perpendicular axis at one of its end, then it's momentum inertia must be:

According to Newton 2nd law, the torque required to exert on this rod to achieve such angular acceleration is

So the force acting on the other end to generate this torque mush be:

The answer is B
explanation
Explanation:
The range <em>R</em> of a projectile is given by

The maximum range
occurs when
. Let
be the angle above or below 45°. Now let's look at the ranges brought about by these angle differences.
<u>Case</u><u> </u><u>1</u><u>:</u><u> </u><u>A</u><u>ngle</u><u> </u><u>above</u><u> </u><u>4</u><u>5</u><u>°</u>
We can write the range as



<u>Case</u><u> </u><u>2</u><u>:</u><u> </u><u>Angle</u><u> </u><u>below</u><u> </u><u>45</u><u>°</u>
We can write the range as



Note that the equations (1) and (2) are identical. Therefore, the ranges are equal if they differ from 45° by the same amount.
Answer:
sorry i dont know ur language