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Yuri [45]
4 years ago
10

Which sequence of transformations would yield a square similar to the original square but not congruent

Mathematics
2 answers:
Mama L [17]4 years ago
8 0

The sequence of transformations that would yield a square similar to the original square but not congruent are reflection and dilation.

Step-by-step explanation:

Reflection will map a square to its image.The size and shape are maintained.In Dilation the square image and the original are similar but are not congruent because the scale factor used in dilation will alter the shape and size of the image making the image and original square not congruent.

Learn More

  • brainly.com/question/11390880

Keywords : transformations, congruent , square, dilation

#LearnwithBrainly

Mkey [24]4 years ago
5 0

Answer:

the answer is B

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 0
3 years ago
Please help with number 33 and 34!
mariarad [96]
Problem 33

For each number, generate a factor tree. This is where you break a number down into smaller factors in a visual "tree" like style. The idea is to factor down to the prime factors and then you circle the common primes between each number. The values you circle are then multiplied if you circle more than one value in each tree. 

-------------------------------------------------------------------------------

Problem 34

Xiao factored correctly but didn't pull out the GCF. So he didn't factor fully. In the case of 60 and 90, the GCF is 30. This is the largest shared factor between the two values. So we can pull out 30 to get
60+90 = 30*2+30*3 = 30*(2+3)

I'm basically using the distributive property in reverse. You can distribute the 30 back in and get 60+90 again. Notice how the inner stuff 2 and 3 have no factors in common other than 1. 

7 0
4 years ago
Can you please help me in this question :o)
Maurinko [17]
Which question do you need help on?
6 0
3 years ago
Write a rule for the nth term of the sequence. Then find a20. Assume the first termis a₁. 86, 79, 72, 65…
hodyreva [135]

Answer:

an = a(n-1) - 7

Step-by-step explanation:

the second term is smaller than the first term 7.

a20 = a19 - 7

a19 = a18 - 7

=> a20 = (a18 - 7) - 7

Then you can accumalate until a1

-> a20 = a1 - 19*7 = 86 - 19*7 = -47

5 0
3 years ago
Question 4 (4 points
aalyn [17]

Answer:

It is True 200% legit!

Step-by-step explanation:

4 0
3 years ago
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