Answer:
B. <em>They will never have the same amount of water because the solution to the system is (-2,18). It is not possible to have time be -2 hours. </em>
Step-by-step explanation:
Let us assume that
x = the number of hours the tanks are filling,
y = the number of gallons in the tank.
Tank 1 contains 12 gal of water and is leaking at a constant rate of 3 gal/h.
As the water is decreasing with time, so rate of change will be negative, so the equation will be
--------------1
Tank 2 contains 8 gal of water and is leaking at a constant rate of 5 gal/h.
As the water is decreasing with time, so rate of change will be negative, so the equation will be
--------------2
As we have to calculate the time where the amount of water left in the tanks will be same, so
So, at x= -2, y will be
Here, x which is time, is negative i.e solution is not possible.
Also the value of y comes out to be 18, which is impossible. Because there is not even 18 gal of water, so how can they both have 18 gal water.
