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dangina [55]
3 years ago
11

In percent, the “whole” is 100. What is the “whole” in decimal form?

Mathematics
1 answer:
tekilochka [14]3 years ago
8 0

1. You divide by 100 to find the decimal version of any percentage, and do the opposite for vise versa

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I need helpp :D cuz if i dont get all my missing bellringers in i wont get to go to a concerttttt
ollegr [7]

Answer:

b and e

Step-by-step explanation:

3 0
2 years ago
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( 2x + 1 ) + ( 3x+2 ) =
MrRa [10]

Answer: 5x+3

Let's go over this problem step by step:

First, you need to combine all the line terms.

2x + 1 + 3x + 2

Next, you get this equation:

( 2x + 3x ) + ( 1 + 2 )

2x and 3x is 5x. 1 and 2 is 3.

So your final answer is 5x+3.

7 0
3 years ago
What are the types of roots of the equation below?<br> - 81=0
Tju [1.3M]

Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0. This can be obtained by finding root of the equation using algebraic identity.    

<h3>What are the types of roots of the equation below?</h3>

Here in the question it is given that,

  • the equation x⁴ - 81 = 0

By using algebraic identity, (a + b)(a - b) = a² - b², we get,  

⇒ x⁴ - 81 = 0                      

⇒ (x² +  9)(x² - 9) = 0

⇒ (x² + 9)(x² - 9) = 0

  1. (x² -  9) = (x² - 3²) = (x - 3)(x + 3) [using algebraic identity, (a + b)(a - b) = a² - b²]
  2. x² + 9 = 0 ⇒ x² = -9 ⇒ x = √-9 ⇒ x= √-1√9 ⇒x = ± 3i

⇒ (x² + 9) = (x - 3i)(x + 3i)

Now the equation becomes,

[(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

Therefore x + 3, x - 3, x + 3i and x - 3i are the roots of the equation

To check whether the roots are correct multiply the roots with each other,

⇒ [(x - 3)(x + 3)][(x - 3i)(x + 3i)] = 0

⇒ [x² - 3x + 3x - 9][x² - 3xi + 3xi - 9i²] = 0

⇒ (x² +0x - 9)(x² +0xi - 9(- 1)) = 0

⇒ (x² - 9)(x² + 9) = 0

⇒ x⁴ - 9x² + 9x² - 81 = 0

⇒ x⁴ - 81 = 0

Hence Option B, that is Two Complex and Two Real which are x + 3, x - 3, x + 3i and x - 3i, are the types of roots of the equation x⁴ - 81 = 0.

Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: What are the types of roots of the equation below?

x⁴ - 81 = 0

A) Four Complex

B) Two Complex and Two Real

C) Four Real

Learn more about roots of equation here:

brainly.com/question/26926523

#SPJ9

5 0
1 year ago
Factorise 10+5d help me plssssss
aleksley [76]

5(2 + d)
Since 5 is divisible by 10 and 5, we can factor out a 5 from both terms.
8 0
3 years ago
Tell whether the graph of the Quadratic function y=-3x squared +x+1 opens upward or downward
8_murik_8 [283]

Answer:

down

Step-by-step explanation:

y = -3x^2 +x +1

The coefficient of the x^2 term is negative so it opens facing down

X^2 coeffient

- means down

+ mean up

8 0
3 years ago
Read 2 more answers
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