probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
learn more about of probability here
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Answer:
0.0208<p<0.0592
Step-by-step explanation:
-Given the sample size is 400 and the desired proportion is 16.
-The confidence interval can be determined as follows:
#We the use this proportion to find the CI at 95%:
![CI=0.04\pm 1.96\times \sqrt{\frac{0.04(1-0.04)}{400}}\\\\=0.04\pm 0.0192\\\\=[0.0208,0.0592]](https://tex.z-dn.net/?f=CI%3D0.04%5Cpm%201.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.04%281-0.04%29%7D%7B400%7D%7D%5C%5C%5C%5C%3D0.04%5Cpm%200.0192%5C%5C%5C%5C%3D%5B0.0208%2C0.0592%5D)
Hence, the 95% confidence interval is 0.0208<p<0.0592
The answer is P=F/A I had a quiz on these
A coefficient is a numerical or constant quantity placed before and multiplying the variable in an algebraic expression (e.g. 4 in 4x).
The 2 and + are out since they don't have variables(and the + is just a +).
So 4 and x are left. x is a variable, not a coefficient, so the last(and correct) answer is 4.
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hope it helps
Answer:
i saed to answer it and it didnt show me the image so im conf
Step-by-step explanation:
so probably they are, unlees one is acxute and the other is obtuse then.... ur on ur own buddy,
