Answer:
x(3y - 1) and (2a - 3)(2a + 3)
Step-by-step explanation:
(1)
3xy - x ← factor out x from each term
= x(3y - 1)
(2)
4a² - 9 ← is a difference of squares and factors in general as
a² - b² = (a - b)(a + b) , then
4a² - 9
= (2a)² - 3²
= (2a - 3)(2a + 3)
 
        
             
        
        
        
Answer:
The null hypo would be the difference is greater than 0
so the alternate hypothesis would be less than or equal to 0
H1: µd ≤ 0
 
        
             
        
        
        
Answer:
x=0,3
Step-by-step explanation:
start by dividing every term by 3
x^3-3x^2+x-3
group into 2 terms
(x^3-3x^2)+(x-3)
simplify as much as you can
x^2(x-3)+(x-3)
combine terms
(x^2)(x-3)
x=3, 0
 
        
             
        
        
        
Answer:
1: 3\sqrt2 - \sqrt14
2: \sqrt21 - 2\sqrt(7)
3: 4\sqrt3 - \sqrt15
4: 2\sqrt5 - \sqrt10
5: -3 + 3\sqrt5
I already gave you these answers man
Step-by-step explanation:
 
        
             
        
        
        
25----------5 and 5--------------5 and 1 ------------5 and 1