Ask question

Ask question

All categories

3 years ago

6

What are (a) the x component and (b) the y component of a vector in the xy plane if its direction is 250° counterclockwise from

the positive direction of the x axis and its magnitude is 7.3 m?

1 answer:

forsale [732]3 years ago

4 0

Answer:

(-2.497, -6.860)

Step-by-step explanation:

For any magnitude r and direction θ, the translation to rectangular coordinates is ...

(r, θ) ⇒ (x, y)

(r, θ) ⇒ (r·cos(θ), r·sin(θ))

Your coordinates translate to ...

(7.3, 250°) ⇒ (7.3·cos(250°), 7.3·sin(250°)) ≈ (-2.497, -6.860)

You might be interested in

The points plotted below satisfy a polynomial. In what ranges of x-values must there be a root of the graph? Check all that appl

lisov135 [29]

Answer:

not sure,but I think the answer is 3 to 4

6 0

3 years ago

Find the missing angle<br> measures marked with<br> question marks.

slavikrds [6]

Answer:

First one- The ? across from 70 degrees is 70 degrees, and the ones on the side are both 110 degrees.

The second one- The one across 53 degrees is 53 degrees and the ones are the side are both 127 degrees.

Step-by-step explanation:

Take the shown angle and subract that by 180 degrees to get your answer for the missing angles. And the one across from the shown angle is the same number.

Hope this helped im not sure if its right though.

6 0

3 years ago

1. What is the solution of the system?

andreyandreev [35.5K]

Answer:

The given system of equations has solutions below:

1) The solution is (2,3)

2) The solution is ( $\frac{-8}{7}, \frac{5}{7}$ )

3) The solution is infinitely many solutions

4) No solution

Step-by-step explanation:

Given system of equation are

$-x+2y=4\hfill (1)$

$-4x+y=-5\hfill (2)$

To solve equation by using elimination method

Multiply eqn (2) into 2

$-8x+2y=-10\hfill (3)$

Now subtracting (1) and (3)

$-x+2y=4$

$-8x+2y=-10$

_________________

7x=14

x= $\frac{14}{7}$

$x=2$

Substitute x=2 in equation (1)

-2+2y=4

2y=4+2

$y=\frac{6}{2}$

y=3

Therefore the solution is (2,3)

2) Given equation is

$-2x+y=3\hfill (1)$

4y-4=x

Rewritting as below

$x-4y=-4\hfill (2)$

To solve equation by using elimination method

multiply (2) into 2

$2x-8y=-8\hfill (3)$

Adding (1) and (3)

-2x+y=3

2x-8y=-8

________

-7y=-5

$y=\frac{5}{7}$

substitute $y=\frac{5}{7}$ in (1)

$-2x+\frac{5}{7}=3$

$-2x=3-\frac{5}{7}$

$-2x=\frac{21-5}{7}$

$x=-\frac{8}{7}$

Therefore the solution is ( $\frac{-8}{7},\frac{5}{7}$ )

3) Given equation is $6x+2y=10\hfill (1)$

$3x+y=5\hfill (2)$

equation (1) can be written as

2(3x+y)=10

$3x+y=\frac{10}{2}$

3x+y=5

Therefore equations (1) and (2) are same therefore it has infinitely many solutions

4) Given equation is $-x-2y=14\hfill (1)$

$-2x-4y=12\hfill (2)$

multiply equation (1) into 2

$-2x-4y=28\hfill (3)$

To solve equation by using elimination method

subtracting (2) and (3)

-2x-4y=28

-2x-4y=12

_______

$28\neq -12$

therefore it has no solution

4 0

2 years ago

What are the slope and y-intercept of the equation 2x - 5y = -10?

sergiy2304 [10]

Answer:

Step-by-step explanation:

y=2/5x+2

x= 5/2y-5

hopefully this works

7 0

3 years ago

How would 9/25 as a percent

Over [174]

36% is the answer to the question

8 0

3 years ago

Read 2 more answers