Angle at point A = 180 - 90 - 40 = 50 degrees
To find 2 remaining lengths of sides of triangle we just need to use basic trigonometry.
cos40 = 10/AC => AC = 10/cos40 = 13.05
tan40 = AB/10 => AB = 10*tan40 = 8.39
If we want to check this we can use Pythagoras theorem:
AB^2 + BC^2 = AC^2 and see that lengths that we calculated are correct.
Answer:
8x^2-x-8
Step-by-step explanation:
6x^2 + 3x – 9-(- 2x^2 + 4x – 1 )
6x^2 + 3x – 9+2x^2 - 4x + 1
6x^2+2x^2+ 3x- 4x -9+1
8x^2-x-8
Answer:
the answer is w^40
Step-by-step explanation: