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Andreyy89
3 years ago
12

2. What is the distance between the points M(-8,11) and N(3,7)?

Mathematics
1 answer:
ivolga24 [154]3 years ago
6 0

Answer:

I'm not sure I feel like it's A

Step-by-step explanation:

-8 is 11 units away from 3 but I do not know where the 7 came from for answer A.

If I were you I would not trust my answer

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-2(3 + 4x)<br><br>I need help​
11Alexandr11 [23.1K]

Answer:

-6-8x

Step-by-step explanation:

distribute and multiply

4 0
3 years ago
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A set of equations is given below
Alex_Xolod [135]

Answer:

No solution

Step-by-step explanation:

This is no solution due to the fact that the slope of both of the equation are the same. So they are parallel. If the b value is the same then it is infinitely many solutions. Due to the fact that the b value is not the same they are a set of parallel line. Parallel line do not touch or intersect ever so there for this is a no solution set.

4 0
3 years ago
A gas tank on a car holds 16 gallons of gasoline and can travel 480 miles on a full tank. How many miles can the car travel usin
tamaranim1 [39]

16 gal... 480 mi
1 gal... 480/16 = 30 mi
9 gal.. 30*9 = 270 mi

4 0
2 years ago
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HELP ASAP!right answer I’ll give you a crown
faltersainse [42]

Answer:

y=-\frac{3}{2}x+1

Step-by-step explanation:

Slope-intercept form means

y=mx+c

where m is given its the slope which is -\frac{3}{2} and we have the coordinates x and y which is (4, -5) and we need to find the value of c which is the y-intercept so we insert all these values into the equation so ,

y=mx+c

-5 = -\frac{3}{2}(4)+c

-5=-6+c

c=1

now we know the value of slope which is given -\frac{3}{2} and we found the value of which is 1 so we put these values into our original slope-intercept form equation

y=mx+c\\\\y=-\frac{3}{2}x+1

4 0
3 years ago
Match each graph with its corresponding equation
s344n2d4d5 [400]
The equation of the parabolas given will be found as follows:
a] general form of the parabolas is:
y=k(ax^2+bx+c)
taking to points form the first graph say (2,-2) (3,2), thus
y=k(x-2)(x-3)
y=k(x^2-5x+6)

taking another point (-1,5) 
5=k((-1)^2-5(-1)+6)
5=k(1+5+6)
5=12k
k=5/12
thus the equation will be:
y=5/12(x^2-5x+6)

b] Using the vertex form of the quadratic equations:
y=a(x-h)^2+k
where (h,k) is the vertex
from the graph, the vertex is hence: (-2,1)
thus the equation will be:
y=a(x+2)^2+1
taking the point say (0,3) and solving for a
3=a(0+2)^2+1
3=4a+1
a=1/2
hence the equation will be:
y=1/2(x+2)^2+1


5 0
3 years ago
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