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Radda [10]
4 years ago
14

The price per gallon of gasoline changes often. Most drivers pay close attention to those changes. Find the percent change in pr

ice for each of these cases.
a) increase from $4.00 per gallon to $4.20
b) increase from $3.00 per gallon to $3.75
c) decrease from $3.75 per gallon to $3.00
Mathematics
1 answer:
Jlenok [28]4 years ago
6 0
A) The amount of change is .20 (20 cents) so we need to find what percent of $4.00 is .20...
4 * x = .20
x = .20/4 = .05

Multiply by 100 (move decimal 2 places to the right) to change decimal to percent.

.05 = 5% increase

b)The increase is .75.  What percent of 3.00 is .75

3 * x = .75
x = .75/3
x = .25 x 100 = 25% increase

c) The amount of change is .75 but this time we are going from 3.75 to 3.00 so we find out what percent .75 is of 3.75.

3.75 * x = .75
x = .75/3.75
x = .20 x 100 = 20% decrease
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soldier1979 [14.2K]

28% decrease

Solution:

Calculate percentage change

from V1 = 25 to V2 = 18

(V2−V1)|V1|×100

=(18−25)|25|×100

=−725×100

=−0.28×100

=−28%change

=28%decrease

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Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

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2 years ago
What is the constant of proportionality in the equation y = 5/9 x ?
Mazyrski [523]

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6 0
3 years ago
Greg and Erin start at the same point and begin running in different directions. Greg is running east at a speed of 7 miles per
AveGali [126]

Answer: The time at which the distance between the two is 150 miles is 1.3 hr.

Step-by-step explanation:

Step 1: Sketch the problem as shown in the attached image.

The problem can be solved using Pythagoras theorem since the sketch is a right angled triangle.

It follows the equation x² + y² = 15².

The distance covered by Greg is given by <em>x mi</em>, and that of Erin is given by <em>y mi</em>.

Step 2: To derive the distance covered by Erin and Greg, we use the formula <em>Speed = distance ÷ time.</em>

Which by cross-multiplying gives <em>distance = speed × time</em>.

Let time taken to cover the distance be <em>t h</em>.

Given that Speed of Erin is 9 mph and that of Greg is 7 mph.

Hence, distance covered by Greg, x = 7 × t = 7t.

Distance covered by Erin, y = 9 × t = 9t.

Step 3: Insert the terms x and y into the Pythagoras equation x² + y² = 15² and solve for <em>time t.</em>

(7t)² + (9t)² = 15²

49t² + 81t² = 225

(49 + 81)t² = 225

      t² = 225/(49 + 81)

      t² = 225/130

      t² = 1.730769231

       t = √1.730769231

       t = 1.315587029

t = 1.3hr

Hence the time at which the distance between the two is 150 miles is 1.3 hr.

4 0
3 years ago
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