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Feliz [49]
3 years ago
9

At which intervals is the function linear or nonlinear?

Mathematics
1 answer:
NeX [460]3 years ago
5 0

Answer:

Linear                                    non-linear

x<2 , x>5                           2<x<5

Step-by-step  explanation:

When a function is linear then the graph is a straight line

When the function is not linear then the graph is like a curve

From x = - infinity to 2 the graph is a straight line

So from - infinity to 2, the function is linear, that is x<2 function is linear

from 2  to 5 the graph is like a curve , so it is not linear

2<x<5 , the function is not linear

From x = 5 to infinity the graph is a straight line

So from 5 to infinity, the function is linear, that is x>5 function is linear

You might be interested in
How many zeros are in the product (6x5)x103
Serga [27]
If you multiply 6 * 5 you get 30.  30 * 103 = 3,090

There are 2 zeros in the product of (6x5)x103
4 0
3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
Read 2 more answers
I will give brainliest!
Makovka662 [10]
I would think the answer is 3, sorry if i cant help. 
3 0
3 years ago
Peter walks 30 feet away from his house and places a mirror on the ground. He backs 6 feet away from the mirror so that he can s
Natali [406]
Work is in the attached picture. Whenever you are given a problem like this, draw it out. It makes it a lot easier!

The house is 25 feet tall.

4 0
3 years ago
Write the equation of the line that has a slope of 2 and passes through the point (-3,4).
dalvyx [7]

Answer:

The answer to your question is letter D

Step-by-step explanation:

Data

slope = m = 2

Point (-3, 4)

Process

1.- Substitute the data in the line equation

                     y - y1 = m(x - x1)

                     y - 4 = 2 (x + 3)

2.- Expand

                     y - 4 = 2x + 6

3.- Solve for y and simplify

                     y = 2x + 6 + 4

                     y = 2x + 10

3 0
3 years ago
Read 2 more answers
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